Answer:
2577 K
Explanation:
Power radiated , P = σεAT⁴ where σ = Stefan-Boltzmann constant = 5.6704 × 10⁻⁸ W/m²K⁴, ε = emissivity of bulb filament = 0.8, A = surface area of bulb = 30 mm² = 30 × 10⁻⁶ m² and T = operating temperature of filament.
So, T = ⁴√(P/σεA)
Since P = 60 W, we substitute the vales of the variables into T. So,
T = ⁴√(P/σεA)
= ⁴√(60 W/(5.6704 × 10⁻⁸ W/m²K⁴ × 0.8 × 30 × 10⁻⁶ m²)
= ⁴√(60 W/(136.0896 × 10⁻¹⁴ W/K⁴)
= ⁴√(60 W/(13608.96 × 10⁻¹⁶ W/K⁴)
= ⁴√(0.00441 × 10¹⁶K⁴)
= 0.2577 × 10⁴ K
= 2577 K
B would be the correct answer because organic things are made from living things such as,plants
Answer: B. Sensation
Explanation:
Sensation is input about the physical world obtained by our sensory receptors, and perception is the process by which the brain selects, organizes, and interprets these sensations. In other words, senses are the physiological basis of perception. Perception of the same senses may vary from one person to another because each person’s brain interprets stimuli differently based on that individual’s learning, memory, emotions, and expectations.
The sensitivity of a given sensory system to the relevant stimuli can be expressed as an absolute threshold. Absolute threshold refers to the minimum amount of stimulus energy that must be present for the stimulus to be detected 50% of the time.
Sometimes, we are more interested in how much difference in stimuli is required to detect a difference between them. This is known as the just noticeable difference (jnd) or difference threshold.
Answer:
Option D. ⁸⁵₃₆Kr
Explanation:
⁸⁵₃₅Br —> ⁰₋₁e + ?
Let ⁿₘZ represent the unknown.
Thus, the equation becomes:
⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ
Next, we shall determine n, m and Z as follow:
85 = 0 + n
85 = n
Thus,
n = 85
35 = –1 + m
Collect like terms
35 + 1 = m
36 = m
Thus,
m = 36
ⁿₘZ => ⁸⁵₃₆Z = > ⁸⁵₃₆Kr
Thus, the equation:
⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ
Becomes:
⁸⁵₃₅Br —> ⁰₋₁e + ⁸⁵₃₆Kr
Answer:
4.38 × 10⁻³ A
0.395mΩ
452 µΩ
Explanation:
(a)the current in each strand is = the total current/ number of strand
0.876/ 200 = 4.38 × 10⁻³ A
(b) potential difference = IR
the total resistance = 2.26 µΩ × 0.876
= 0.395mΩ
c) resistance of the cable = 2.26 µΩ × 200
=452 µΩ