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Nadusha1986 [10]

2 years ago

7

I need help ASAP!!!! Here’s the question. Stephanie is going to buy an ice cream cone. She can pick a sugar cone or a waffle con

e. She can have vanilla, chocolate, or mint ice cream. How many possible combinations of ice cream cones can she have?

1 answer:

PolarNik [594]2 years ago

7 0

Answer:

Six

Explanation:

Assuming she can only have ONE flavor in her cone

2 cone types * 3 flavors = 6 combos

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You illuminate a slit with a width of 70.3 μm with a light of wavelength 719 nm and observe the resulting diffraction pattern on

Zielflug [23.3K]

Answer:

4.3 cm

Explanation:

We are given that

Width,d=70.3 $\mu m=70.3\times10^{-6} m$

$1\mu m=10^{-6} m$

Wavelength, $\lambda=719 nm=719\times 10^{-9} m$

$1nm=10^{-9} m$

$r=2.11 m$

We have to find the width in cm of the pattern.

The angle for the first minimum m=1

$sin\theta_{min}\approx \theta=\frac{\lambda}{d}=\frac{719\times 10^{-9}}{70.3\times 10^{-6}}=0.0102 rad$

$y=r\theta=2.11\times 0.0102=0.0215 m$

The width of the pattern= $2y=2\times 0.0215=0.043 m=0.043\times 100=4.3 cm$

8 0

3 years ago

Is it true or false that A proton traveling to the right moves in between the two large plates. A vertical electric field, point

Lelu [443]

Answer:

False

Explanation:

In the question it is given that a proton travels in the right moves in between the two plates. An electric field that is pointing in the vertically upward direction has magnitude of 3 N/C. The electric field is produced by the plates.

Now from here we can conclude that the direction of the force acting on the proton when the proton is in between the plates acts in the downward direction. While the electric field lines points in the upward direction. Thus the electric point will not be in the direction of the force that acts on the proton.

3 0

3 years ago

A capacitor with initial charge q0 is discharged through a resistor. a) In terms of the time constant τ, how long is required fo

-BARSIC- [3]

Answer:

It would take $\tau(\ln 9 - \ln 8)$ time for the capacitor to discharge from $q_0$ to $\displaystyle \frac{8}{9} \, q_0$ .

It would take $\tau(\ln 9 - \ln 7)$ time for the capacitor to discharge from $q_0$ to $\displaystyle \frac{7}{9}\, q_0$ .

Note that $\ln 9 = 2\,\ln 3$ , and that $\ln 8 = 3\, \ln 2$ .

Explanation:

In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is $\tau$ , and the initial charge of the capacitor be $q_0$ . Then at time $t$ , the charge stored in the capacitor would be:

$\displaystyle q(t) = q_0 \, e^{-t / \tau}$ .

<h3>a)</h3>

$\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{8}{9}\, q_0$ .

Apply the equation $\displaystyle q(t) = q_0 \, e^{-t / \tau}$ :

$\displaystyle \frac{8}{9}\, q_0 = q_0 \, e^{-t/\tau}$ .

The goal is to solve for $t$ in terms of $\tau$ . Rearrange the equation:

$\displaystyle e^{-t/\tau} = \frac{8}{9}$ .

Take the natural logarithm of both sides:

$\displaystyle \ln\, e^{-t/\tau} = \ln \frac{8}{9}$ .

$\displaystyle -\frac{t}{\tau} = \ln 8 - \ln 9$ .

$t = - \tau \, \left(\ln 8 - \ln 9\right) = \tau(\ln 9 - \ln 8)$ .

<h3>b)</h3>

$\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{7}{9}\, q_0$ .

Apply the equation $\displaystyle q(t) = q_0 \, e^{-t / \tau}$ :

$\displaystyle \frac{7}{9}\, q_0 = q_0 \, e^{-t/\tau}$ .

The goal is to solve for $t$ in terms of $\tau$ . Rearrange the equation:

$\displaystyle e^{-t/\tau} = \frac{7}{9}$ .

Take the natural logarithm of both sides:

$\displaystyle \ln\, e^{-t/\tau} = \ln \frac{7}{9}$ .

$\displaystyle -\frac{t}{\tau} = \ln 7 - \ln 9$ .

$t = - \tau \, \left(\ln 7 - \ln 9\right) = \tau(\ln 9 - \ln 7)$ .

7 0

3 years ago

Why does water level fall initially after it is heated

qwelly [4]

Answer:

dont ask me

Explanation:

6 0

3 years ago

Read 2 more answers

. Find the buoyant force exerted on a ball with radius of 2 meters, when the ball is entirely immersed in the water.

almond37 [142]

Explanation:

Buoyancy force is equal to the weight of the displaced fluid:

B = ρVg

where ρ is the density of the fluid,

V is the volume of the displaced fluid,

and g is the acceleration due to gravity.

The fluid is water, so ρ = 1000 kg/m³.

The volume displaced is that of a sphere with radius 2 m:

V = 4/3 π r³

V = 4/3 π (2 m)³

V ≈ 33.5 m³

The buoyancy force is therefore:

B = (1000 kg/m³) (33.5 m³) (9.8 m/s²)

B ≈ 328,400 N

Round as needed.

8 0

3 years ago