All categories

3 years ago

The formula for calcium oxide is CaO. What are the formulas for magnesium oxide and strontium oxide?

Chemistry

2 answers:

Hunter-Best [27]3 years ago

8 0

Answer:

Formula of magnesium oxide is MgO and formula of strontium oxide is SrO

Explanation:

Ca, Mg and Sr are same group bivalent metals.

Oxygen is a bivalent element

In general, formula of a compound made of a cation $M^{x+}$ and an anion $A^{y-}$ is $M_{y}A_{x}$ for $x\neq y$

When x = y, formula of the compound becomes MA

As both these metals and oxygen are bivalent therefore formula of magnesium oxide is MgO and formula of strontium oxide is SrO.

Karo-lina-s [1.5K]3 years ago

5 0

Answer:

MgO

Explanation:

You might be interested in

Water glass is found in

klemol [59]

Answer:

liquid form

Explanation:

am i right? if right like

5 0

3 years ago

Read 2 more answers

How many moles of water are formed from 0.65 moles of oxygen?

sleet_krkn [62]

Answer:

two moles of water

hope this helps

7 0

3 years ago

What is the urinary system and what does it do

nadezda [96]

The urinary system filters and gets rid of waste from the body.

7 0

2 years ago

Read 2 more answers

Thermochemistry

max2010maxim [7]

THe Answer is 105 J

hope this helps and please brainliest, I was first :)

4 0

2 years ago

In the spring of 1984, concern arose over the presence of ethylene dibromide, or EDB, in grains and cereals. EDB has the molecul

Lady bird [3.3K]

869.6 × 10¹⁴ molecules of EDB

Explanation:

We have 1.9 lb of flour with a EDB concentration of 31.5 ppb.

We need to transform lb in grams.

1 lb = 453.6 grams

1.9 lb = (1.9 × 453.6) / 1 = 861.8 grams

Now we determine the number of molecules of EDB in the sample by devise the following reasoning:

if we have 31.5 × 10⁻⁹ g of EDB in 1 g of sample

then we have X g of EDB in 861.8 g of sample

X = (31.5 × 10⁻⁹ × 861.8) / 1 = 27146.7 × 10⁻⁹ g of EDB

Molecular mass of EDB (C₂H₄Br₂) = 188 g/mole

Taking in account that 1 mole of any substance contains 6.022 × 10²³ (Avogadro’s number) molecules we devise the following reasoning:

if 188 g of EDB contains 6.022 × 10²³ molecules

then 27146.7 × 10⁻⁹ g of EDB contains Y molecules

Y = (27146.7 × 10⁻⁹ × 6.022 × 10²³) / 188 = 869.6 × 10¹⁴ molecules of EDB

Learn more:

about Avogadro’s number

brainly.com/question/1445383

#learnwithBrainly

8 0

3 years ago

Read 2 more answers