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3 years ago

The trajectory of a projectile always ________________.

Physics

1 answer:

sattari [20]3 years ago

8 0

Answer:

c) curves downward, below the initial velocity vector

Explanation:

A projectile is usually launched from a height, where it is launched with an initial velocity. From that point the gravitational force begins to act on the projectile causing it to decay. As time passes, the projectile advances but its height decreases. So its trajectory is curved downward, below the initial velocity vector.

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The magnetic field due to a utility wire is 0.10 mT when you are at a distance of 10 meters from it. What current (in Amperes) f

ale4655 [162]

Answer:

I = 5000 A

Explanation:

We will use Ampere's Law to calculate the current:

$B = \frac{\mu I}{2\pi r}\\\\$

where,

B = Magnetic Field Strength = 0.1 mT = 1 x 10⁻⁴ T

μ = Permeability of Free Space = 4π x 10⁻⁷ N/A²

I = Current = ?

r = radius = 10 m

Therefore,

$1\ x\ 10^{-4}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(I)}{2\pi(10\ m)}\\\\I = \frac{(1\ x\ 10^{-4}\ T)(2\pi (10\ m))}{4\pi\ x\ 10^{-7}\ N/A^2}$

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3 years ago

During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t

leonid [27]

The instant it was dropped, the ball had zero speed.

After falling for 1 second, its speed was 9.8 m/s straight down (gravity).

Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.

Falling for 1 second at an average speed of 4.9 m/s, is covered <em>4.9 meters</em>.

ANYTHING you drop does that, if air resistance doesn't hold it back.

7 0

3 years ago

Read 2 more answers

Can someone help me ASAP please

aleksandr82 [10.1K]

The answer is c☺️ hope u have a good day

4 0

3 years ago

A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field

Sophie [7]

Explanation:

direction of electric field is same as that of force experienced by the test charge

8 0

3 years ago

A 25.0-gram bullet enters a 2.25-kg watermelon with a speed of 220 m/s and exits the opposite side with a speed of 110 m/s. If t

umka21 [38]

Answer:

3.67 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

mu+m'u' = mv+m'v'............................... Equation 1

Where m = mass of the bullet, m' = mass of the watermelon, u = initial velocity of the bullet, u' = initial velocity of the watermelon, v = final velocity of the bullet, v' = final velocity of the watermelon.

make v' the subject of the equation,

v' = (mu+m'u'-mv)/m'....................... Equation 2

Given: m = 25 g = 0.025 kg, u = 220 m/s, m' = 2.25 kg, u' = 0 m/s ( at rest), v = 110 m/s.

Substitute into equation 2

v' =[ (0.025×220) +(2.25×0)+(0.025×110)]/2.25

v' = 3.67 m/s.

Hence the velocity of the watermelon = 3.67 m/s

7 0

4 years ago