The x-acis of a trajectory represents its C
Answer:
Spring constant, k = 5483.11 N/m
Explanation:
It is given that,
Mass of the organ, m = 2 kg
The natural period of oscillation is, T = 0.12 s
Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :



k = 5483.11 N/m
So, the spring constant for the spring in the scientist's model is 5483.11 N/m.
Tendon Sheath - is a specialized bursa that wraps around a tendon to reduce friction.
<h3>What is Tendon Sheath ?</h3>
Tendon Sheath is a thin layer of tissue, surrounds each tendon in our body. The tendon sheath can also be called synovial lining or fibrous sheath. Tendon sheaths help to protect tendons from abrasive damage as they move.
Connection between Bursa and Tendon Sheath : Bursae are small fluid-filled sacs that can lie under a tendon, cushioning the tendon and protecting it from the injury. Bursae also provides an extra cushioning to adjacent structures that otherwise might rub against each other, which will cause wear and tear ( example, between a bone and a ligament ) .
So, lastly we can say that Tendon Sheath is the specialized bursa that wraps around a tendon to reduce friction.
To know more about Tendon Sheath please click here : brainly.com/question/17087116
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Answer:
Explained below
Explanation:
Newton's first law of motion: This law states that an object will remain at rest or continue in constant motion except it's acted upon by an external force. In projectile motion, the horizontal component of velocity will remain unchanged because we ignore air resistance since no force is acting in that horizontal direction.
Newton's second law of motion: This law states that force is the product of mass and acceleration. In projectile the force acts downwards, thus f = mg.
But g = a since internal forces will cancel out.
Thus, F = ma
The expression for the radius and height of the cone can be obtained from
the property of a function at the maximum point.
- The height of the cone is half the length of the radius of the circular sheet metal.
Reasons:
The part used to form the cone = A sector of a circle
The length of the arc of the sector = The perimeter of the circle formed by the base of the cone.

θ/360·2·π·s = 2·π·r
Where;
s = The radius of he circular sheet metal
h = s² - r²
3·r²·s² - 4·r⁴ = 0
3·r²·s² = 4·r⁴
3·s² = 4·r²


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