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3 years ago

An object is moving to the left at a constant speed. Its acceleration is:

Physics

1 answer:

Reil [10]3 years ago

7 0

Answer:

C. Zero acceleration....

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A less-dense liquid of density rho1 floats on top of a more-dense liquid of density rho2. A uniform cylinder of length l and den

Umnica [9.8K]

Answer:

Explanation:

Given

$\rho=density\ of\ cylinder\\\rho_1=less\ dense\ cylinder\\\rho_2=more\ dense\ cylinder$

Suppose V is the volume of a cylinder

Also $L_1=length\ in\ less\ dense\ part\\L_2=length\ in\ dense\ part\\L=length\ of\ cylinder\\V=A\times L\\where\ A=area\ of\ cross-section\\$

Now, we can write

The weight of the cylinder is supported by the buoyant forces of two liquids

$\rho Vg=\rho_1 V_1g+\rho_2 V_2g\\\rho ALg=\rho_1 A\times L_1g+\rho_2 A\times L_2g\\\\\rho L=\rho_1 L_1+\rho_2 L_2\\Also, L=L_1+L_2$

using the above equation we can write

$L_2=\frac{\rho-\rho_1}{\rho_2-\rho_1}\cdot L\\\frac{L_2}{L}=\frac{\rho-\rho_1}{\rho_2-\rho_1}$

5 0

3 years ago

.A cart rolling down an incline for 5.0 seconds has an acceleration of 1.6 m/s2. If the cart has a beginning speed of 2.0 m/s, a

Ilia_Sergeevich [38]

Use the formula,

$\Delta x=v_it+\dfrac12at^2$

where $\Delta x$ is the cart's displacement (from the origin), $v_i$ is its initial speed, $a$ is its acceleration, and $t$ is time.

$\Delta x=\left(2.0\dfrac{\rm m}{\rm s}\right)(5.0\,\mathrm s)+\dfrac12\left(1.6\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)^2$

$\implies\boxed{\Delta x=30\,\mathrm m}$

Alternatively, since acceleration is constant, we have

$\dfrac{v_f+v_i}2=\dfrac{\Delta x}t$

That is, we have these two equivalent expressions for average velocity, where $v_f$ is the cart's final velocity. Solve for $\Delta x$ :

$\dfrac{10\frac{\rm m}{\rm s}+2.0\frac{\rm m}{\rm s}}2=\dfrac{\Delta x}{5.0\,\mathrm s}$

$\implies\boxed{\Delta x=30\,\mathrm m}$

8 0

3 years ago

A man weighing 680N and a woman weighing 500N have the same momentum. What is the ratio of the man's kinetic energy Km to that o

svet-max [94.6K]

Answer:

$\dfrac{K_m}{K_w}=0.734$

Explanation:

given,

weight of the man = 680 N

weight of the woman = 500 N

mass of man = $\dfrac{680}{9.8}$

M_m = 69.4 Kg

mass of woman

= $\dfrac{500}{9.8}$

M_w = 51 Kg

ratio of man's kinetic energy Km to that of the woman Kw

$\dfrac{K_m}{K_w}=\dfrac{\dfrac{P_m^2}{2M_m}}{\dfrac{P_w^2}{2M_w}}$

momentum is same

$\dfrac{K_m}{K_w}=\dfrac{2M_w}{2M_m}$

$\dfrac{K_m}{K_w}=\dfrac{M_w}{M_m}$

$\dfrac{K_m}{K_w}=\dfrac{51}{69.4}$

$\dfrac{K_m}{K_w}=0.734$

3 0

4 years ago

A 4.00 µf capacitor is connected to a 12.0 v battery.

atroni [7]

(a) The capacitance of the capacitor is:
$C=4 \mu F=4 \cdot 10^{-6}F$
and the voltage applied across its plates is
$V=12.0 V$

The relationship between the charge Q on each plate of the capacitor, the capacitance and the voltage is:
$C= \frac{Q}{V}$
and re-arranging it we find the charge stored in the capacitor:
$Q=CV=(4 \cdot 10^{-6} F)(12.0 V)=4.8 \cdot 10^{-5} C$

(b) The electrical potential energy stored in a capacitor is given by
$U= \frac{1}{2}CV^2$
where C is the capacitance and V is the voltage. The new voltage is
$V=1.50 V$
so the energy stored in the capacitor is
$U= \frac{1}{2}(4 \cdot 10^{-6} F)(1.50 V)^2=4.5 \cdot 10^{-6} J$

3 0

3 years ago

Read 2 more answers

7. 100 Joules of work was done to move an object with a force of 15 N. How far did the

worty [1.4K]

Answer:Distance=6.67 (rounded)

Explanation: Work = Force x Distance.

100 Joules of work= force of 15 N x Distance (?)

The work equation given above can be rearranged to find force or distance if the other variables are known:

Distance=Work / force

Distance=100Joules/15 N

Distance=6.67 (rounded)

7 0

3 years ago