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katrin2010 [14]
2 years ago
13

The unsaturated hydrocarbon butadiene (C4H6) dimerizes to 4-vinylcyclohexene (C8H12). When data collected in studies of the kine

tics of this reaction were plotted against reaction time, plots of [C4H6] or ln[C4H6] produced curved lines, but the plot of 1/[C4H6] was linear.
a) What is the rate law for the reaction?
Chemistry
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

The dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

Explanation:

2C_4H_6\rightarrow C_8H_{12}

The rate of the reaction ;

R=k[C_4H_6]^x

As given in the question , that graph of time verses \frac{1}{[C_4H_6]} was linear but plots of [C_4H_6] or \ln[C_4H_6]  was curved.

Generally:

Graph of time verses [concentration] for zero order reaction is linear with negative slope.

Graph of time verses \ln [concentration] for secon order reaction is linear with negative slope.

Graph of time verses \frac{1}{[concentration]} for secon order reaction is linear with positive slope.

So, the dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

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(CH3)2-CH-CH2-O(CH3)3IUPAC NAME
bazaltina [42]

Answer:

1-(tert-butoxy)-2-methylpropane

Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.

Explanation:

<em>Structural formula is attached</em>

IUPAC naming rules

1. start numbering the chain from the functional group. In this compound we        start from oxygen side.

2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.

3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.

4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane

5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane

3 0
3 years ago
Which of the following is NOT a clue that a chemical change has occurred? * 1 point Sugar turns blackish-brown as it is heated.
Vladimir [108]

Answer:

The answer is Steam is produced when water is heated. The color does not change, a precipice is not formed, and the odor does not change!

5 0
3 years ago
An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0
3 years ago
If an atom has 35 protons in the nucleus, how many will it have orbiting nucleus
yan [13]
It will have 35 ''electrons'' . Basically the number of protons in the nucleus of an atom is always equal to the number of electrons but its just that protons are positively charged and electrons are negatively charged.  <span />
8 0
3 years ago
When 4.41g of phosphoric acid (H3PO4) react with 9.25g of barium hydroxide, water and insoluble barium phosphate form. [T/I-7] a
AnnZ [28]

Answer:

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

Explanation:

Let's consider the unbalanced equation that occurs when phosphoric acid reacts with barium hydroxide to form water and barium phosphate. This is a neutralization reaction.

H₃PO₄(aq) + Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

We will balance it using the trial and error method.

First, we will balance Ba atoms by multiplying Ba(OH)₂ by 3 and P atoms by multiplying H₃PO₄ by 2.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

Finally, we will get the balanced equation by multiplying H₂O by 6.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

3 0
3 years ago
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