Answer:
Explination:
Given Data:
Trail 1 Trial 2 Trial 3
Student A 448.0 cm 485.6 cm 463.4 cm
Student B 450.5 cm 441.3 cm 446.8 cm
Student C 422.6 cm 445.2 cm 432.7 cm
Accepted Value = 435.0 cm
Required:
A: Accurate measurement =?
B: Reason for the answer =?
C: Precise measurement =?
D: Reason for the answer =?
Solution:
Student A:
Trail 1: 435.0 cm – 448.0 cm = (13.0 cm greater than accepted value)
Trail 2: 435.0 cm – 485.6 cm = (50.6 cm greater than accepted value)
Trial 3: 435.0 cm – 463.4 cm = (28.4 cm greater than accepted value)
Student B:
Trail 1: 435.0 cm – 450.5 cm = (14.5 cm greater than accepted value)
Trail 2: 435.0 cm – 441.3 cm = (6.3 cm greater than accepted value)
Trial 3: 435.0 cm – 446.8 cm = (11.8 cm greater than accepted value)
Student C:
Trial 1: 435.0 cm – 422.6 cm = (12.4 cm less than accepted value)
Trial 2: 435.0 cm – 445.2 cm = (10.2 cm greater than accepted value)
Trial 3: 435.0 cm – 432.7 cm = (1.3 cm less than accepted value)
A: The 3rd trial of the student C is accurate measurement = 432.7 cm.
B: The 3rd value of students’ C measurement is accurate because it is quite near to the accepted value, i.e. 435.0 cm.
As we know that Accuracy refers to the closeness of a measured value to a standard or known value.
This value has only the difference of 1.3 cm.
435.0 cm – 432.7 cm = (1.3 cm less than accepted value)
All the other have larger difference which is as above.
___________________
Student A:
1. 448.0 cm – 485.6 cm = (37.6 cm far)
2. 485.6 cm – 463.4cm = (22.2 cm far)
Student B:
1. 450.5 cm – 441.3 cm = (9.2 cm far)
2. 441.3 cm – 446.8 cm = (5.5 cm far)
Student C:
1. 422.6 cm – 445.2 cm = (22.6 cm far)
2. 445.2 cm – 432.7cm = (12.5 cm far)
So,
C: The values of Student B are more precise.
D: As we know that Precision refers to the closeness of two or more measurements to each other.
The measurements of student C are more close to each other. The values are only 9.2 cm and 5.5 cm far from each other.
