The correct answer is option 2. A 0.8 M aqueous solution of NaCl has a higher boiling point and a lower freezing point than a 0.1 M aqueous solution of NaCl. This is explained by the colligative properties of solutions. For the two properties mentioned, the equation for the calculation of the depression and the elevation is expressed as: ΔT = -Km and <span>ΔT = Km, respectively. As we can see, concentration and the change in the property has a direct relationship.</span>
The copper wire was sanded before burning in order to make sure that copper metal was exposed on the surface of the wire.
Answer: B
Explanation
The copper wire when placed in atmosphere without coating leads to oxidation of copper metal with respect to the impurities present in the atmosphere.
As copper is electropositive in nature, so electronegative ions present in the universe will try to react with copper and the copper will react easily with other elements.
So generally copper wire is coated with color or polymer coating.
In this case, the copper wire without any coating is sanded, so that the eddy sheets or polishing materials on friction with copper wire will remove the impurities by the electrostatic law of conservation of charges and charge transfer.
As the impurities are removed when copper wire is sanded, the copper atoms will be exposed on the surface of the wire leading to burning of copper in the copper wire.
Answer:
bacteria
Explanation:
The pathogen below is a single-celled organism without a nucleus that can cause illness in a humans.
The answer would be ~sedimentary~
Hope this helps
Have a great day/night
<u>Answer:</u> The temperature when the volume and pressure has changed is 274 K
<u>Explanation:</u>
To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K](https://tex.z-dn.net/?f=P_1%3D760mmHg%5C%5CV_1%3D175L%5C%5CT_1%3D15%5EoC%3D%5B15%2B273%5DK%3D288K%5C%5CP_2%3D640mmHg%5C%5CV_2%3D198L%5C%5CT_2%3D%3FK)
Putting values in above equation, we get:
Hence, the temperature when the volume and pressure has changed is 274 K
