Answer:
The amount of energy transferred to the water is 4.214 J
Explanation:
The given parameters are;
The mass of the object that drops = 5 kg
The height from which it drops = 86 mm (0.086 m)
The potential energy P.E. is given by the following formula
P.E = m·g·h
Where;
m = The mass of the object = 5 kg
g = The acceleration de to gravity = 9.8 m/s²
h = The height from which the object is dropped = 0.086 m
Therefore;
P.E. = 5 kg × 9.8 m/s² × 0.086 m = 4.214 J
Given that the potential energy is converted into heat energy, that raises the 1 g of water by 1°C, we have;
The amount of energy transferred to the water = The potential energy, P.E. = 4.214 J.
Answer:
Training is a way for employers to provide tools to enable employees to protect themselves and others from injuries.
Explanation:
Answer:
h = 10,349.06 W/m^2 K
Explanation:
Given data:
Inner diameter = 3.0 cm
flow rate = 2 L/s
water temperature 30 degree celcius




at 30 degree celcius 

Re = 106390
So ,this is turbulent flow



SOLVING FOR H
WE GET
h = 10,349.06 W/m^2 K