All categories

2 years ago

What forced induction device is more efficient?

Engineering

2 answers:

Anastasy [175]2 years ago

5 0

Answer:

Explanation:

Tanzania [10]2 years ago

5 0

Answer:

Explanation:

You might be interested in

Can anyone tell me what rock this is?

Oksi-84 [34.3K]

Answer: answer is B

Explanation:

8 0

3 years ago

Read 2 more answers

Which of the following Identifies the challenges faced by scientists experimenting with using artificial photosynthesis as

bezimeni [28]

Answer:

The cost and size of materials needed to produce energy

Explanation:

Artificial photosynthesis is a chemical process that uses solar cells instead of chlorophyll to absorb sunlight and convert it into electricity. This process uses artificial leaves that require man-made catalyst to spilt water present in the air into hydrogen and oxygen. It is clear that the reaction requires heat from the sun for energy production thus the technology is expensive to be applied in most areas of the world. Additionally, results obtained from previous undertaken projects of this type has been ineffective and unsustainable because it involves a lot of trial and error.

8 0

2 years ago

Which is an example of a passive solar energy system

Dafna1 [17]

Stone or concrete contraptions

5 0

3 years ago

A slogan promoting STEM

Dominik [7]

Answer:

science technology engineering mathematics

Explanation:

4 0

3 years ago

Two blocks A and B have a weight of 10 lb and 6 lb , respectively. They are resting on the incline for which the coefficients of

sertanlavr [38]

Answer:

Part A- $10.06^\circ$

Part B- 0.1946ft

Explanation:

Block A

Apply force equilibrium equation along x direction.

$\begin{array}{l}\\\sum {{F_x}} = 0\\\\{F_A} + {F_S} - 10\sin \theta = 0\\\end{array}$

Here, ${F_A$ } is friction force on block A and ${F_S$ }is spring force, and \theta is inclination angle.

By substitution

$0.14\,{N_A} + \left( {1.9x} \right)\,{\rm{lb}} \cdot {\rm{ft}} - 10\sin \theta = 0$

Similarly, apply force equilibrium equation along y direction.

$\begin{array}{l}\\\sum {{F_y}} = 0\\\\{N_A} - 10\cos \theta = 0\\\\{N_A} = 10\cos \theta \\\end{array}$

By substitution

$\begin{array}{l}\\0.14\,\left( {10\cos \theta } \right) + \left( {1.9x} \right) - 10\sin \theta = 0\\\\\left( {1.9x} \right) = 10\sin \theta - 1.4\cos \theta \\\end{array}$

Block B

Apply force equilibrium equation along x direction.

$\begin{array}{l}\\\sum {{F_x}} = 0\\\\{F_B} - {F_S} - 6\sin \theta = 0\\\end{array}$

By substitution

$0.24\,{N_A} - \left( {1.9x} \right) - 6\sin \theta = 0$

Apply force equilibrium equation along y direction.

$\begin{array}{l}\\\sum {{F_y}} = 0\\\\{N_B} - 6\cos \theta = 0\\\\{N_B} = 6\cos \theta \\\end{array}$

$\begin{array}{l}\\0.24\,\left( {6\cos \theta } \right) - \left( {1.9x} \right) - 6\sin \theta = 0\\\\\left( {1.9x} \right) = 1.44\cos \theta - 6\sin \theta \\\end{array}$

Calculate the inclination angle when both blocks begin to slide.

$\begin{array}{l}\\10\sin \theta - 1.4\cos \theta = 1.44\cos \theta - 6\sin \theta \\\\16\sin \theta = 2.84\cos \theta \\\\\tan \theta = \frac{{2.84}}{{16}}\\\\\theta = {\tan ^{ - 1}}\left( {\frac{{2.84}}{{16}}} \right)\\\end{array}$

Calculate the change in length of the spring.

$\begin{array}{l}\\\left( {1.9x} \right) = 1.44\cos \left( {10.06^\circ } \right) - 6\sin \left( {10.06^\circ } \right)\\\\1.9x = 0.3697\\\\x = 0.1946\,{\rm{ft}}\\\end{array}$

3 0

3 years ago