Answer:
3.25 ft/s
Explanation:
The crate is of =14-lb=m₁
The angle of inclination is = 40°=Ф
The initial velocity = 0.4 ft/s= v₁
Distance the crate will move is= 0.3 ft =d
The load pulling downwards is = 36 lb= m₂
Acceleration of the pulley, a= m₂g - m₁gsinФ / m₁+m₂ where g= 32.17 ft/s^2
a= 36*32.17 - 14*32.17*sin 40° / 14+36
a=17.37 ft/s^2
Apply the formula for final velocity
V₂²=V₁²+2ad
V₂²=0.4²+ 2*17.37*0.3
V₂²=10.582
V₂ =√10.582 = 3.25 ft/s
Vibrations felt through the floor are due to unbalanced wheels. It would most likely be rear because if it’s the front the steering whee would also vibrate
Answer:
Sorry for the delayed response- Right now I don't have time to give you the answer, but I really want to help so I'll try to phrase it in a easier way to understand things: Basically what you need to do for this problem is find the area of the base of the figure (which means length x width) and then you would simply find the volume of 
by finding the length of each side of the figure, find the length of the figure, find the height of the figure and then find the radius.
Have an amazing day and I hope this can somewhat help :)
Answer:
import java.util.*;
public class BarChart
{
public static void main(String args[])
{
int arr[]=new int[5];
Scanner sc=new Scanner(System.in);
for(int i=0;i<5;i++)
{
while(true){
System.out.println("Enter today's sale for store "+(i+1)+" (negative value not allowed)");
arr[i]=sc.nextInt();
if(arr[i]>0)
break;
}
}
System.out.println("SALES BAR CHART");
for(int i=0;i<5;i++)
{
System.out.println("Store "+(i+1)+": ");
for(int j=0;j<arr[i];j=j+100)
{
System.out.print("*");
}
System.out.println("");
}
}
}
