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Alex
3 years ago
10

Could acetic acid be used in the esterification, instead of acetyl chloride? Why or why not?

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

Yes, acetic acid could be used, but it would not be as effective as acetyl chloride or acetic anhydride. ... However, the acetic anhydride would still be reacting with an alcohol, so nothing changes in that respect. Also, the reaction would need to be done in basic solution.

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On a trip of 555 miles, an automobile consumed 55.5 gallons of gasoline costing $4.55 per gallon.
bagirrra123 [75]

Answer:

0.455

Explanation:

555/55.5 mean 10 miles per gallon, take the price per gallon and divide it by 10. 4.55/10

5 0
3 years ago
What does the host mean when he says that the acid has "donated a proton" to the water?
weqwewe [10]

Answer:

Option B

Explanation:

As Brønsted-Lowry theory states, acids are the ones that can donate protons.

When a proton is donated, it is released to become medium more acidic.

HCl is a strong acid.

HCl (l) + H₂O (l)  →  H₃O⁺ (aq) +  Cl⁻(aq)

These always reffers to strong acid where the dissociation is 100% completed.

In a weak acid, dissociation is not 100% complete, that's why we have an equilibrium.

HA (l) + H₂O (l)  ⇄  H₃O⁺ (aq) +  A⁻(aq)                   Ka

5 0
3 years ago
Part 1: Fill in the blanks below to state Newton’s three laws of motion:
Rainbow [258]

Answer:

all objects will remain at rest, or will continue to move at a constant speed in the same velocity unless acted upon by an unbalanced force. This property is called interia

Explanation:

8 0
3 years ago
Hydrogen is a pure substance represented by the chemical symbol H. Which of the following best describes hydrogen?
Soloha48 [4]

Answer:

B is the answer

Explanation:

Because it a molecular mass of one

3 0
3 years ago
Which of the following should have the highest conductivity? a. 3.0 M NaCl b. 2.1 M Na3PO4 c. 2.4 M CaCl2 d. 3.2 M NH4NO3
Aleks [24]

Answer:

The correct answer is option b, that is, 2.1 M Na₃PO₄.

Explanation:

The solution with the largest concentration of ions will possess the highest conductivity.

a) 3.0 M NaCl

NaCl ⇔ Na⁺ + Cl⁻

Here the total number of ions is 2, therefore, the concentration of ions is 3.0 × 2 = 6.0 M

b) 2.1 M Na₃PO₄

Na₃PO₄ ⇔ 3 Na⁺ + PO₄³⁻

Here the total number of ions i 4. Therefore, the concentration of ions is

2.1 × 4 = 8.4 M.

c) 2.4 M CaCl₂

CaCl₂ ⇔ Ca²⁺ + 2Cl⁻

The total number of ions is 3. Therefore, the concentration of ions is

2.4 × 3 = 7.2 M

d) 3.2 M NH₄NO₃

NH₄NO₃ ⇔ NH₄⁺ + NO₃⁻

The total number of ions is 2. The concentration of ions will be,

3.2 × 2 = 6.4 M

Hence, the highest conductivity will be of 2.1 M Na₃PO₄.

8 0
3 years ago
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