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matrenka [14]
3 years ago
7

Which element has properties most similar to Bromine? A) F B) Kr C) S D) Se

Chemistry
2 answers:
Stells [14]3 years ago
7 0
Fluorine (F) will have properties similar to Bromine (Br) because it belongs to the same group as Bromine.
mezya [45]3 years ago
3 0
The correct answer is flourine
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The amount of dissolved salt in water is know as
Aleksandr [31]

Answer:

The water is solvent and the salt is solute

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For the reaction 2hbr(g)⇌h2(g)+br2(g), k= 2.00×10−19 at 298 k what can be said about this reaction at this temperature? hints fo
Olin [163]

The equilibrium constant k is actually the ratio of the concentration of the products over the concentration of reactants at equilibrium. So if the concentration of products < concentration of reactants, therefore the constant k will be small. But if the concentration of products > concentration of reactants, the constant k will be large. In this case the value is too small (x10^-19), therefore we can say that the reaction favors the reactant side:

 

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3 years ago
Use the following half-reactions to construct a voltaic cell:
velikii [3]

<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

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3 years ago
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NNADVOKAT [17]
Chlorophyll is an example of a pigment.
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