Answer:
2.2 meters
Explanation:
Potential energy, PE created by a charge, q at a radius r from the charge source, Q, is expressed as:
![KE=\frac{kQq}{r}\ \ \ \ \ \ \ ...i](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7BkQq%7D%7Br%7D%5C%20%20%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20...i)
is Coulomb's constant.
#The electric field,
at radius r is expressed as:
![E=\frac{kQ}{r^2}\ \ \ \ \ \ \ \ \ \ ...ii](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BkQ%7D%7Br%5E2%7D%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20...ii)
From i and ii, we have:
![KE=Eqr](https://tex.z-dn.net/?f=KE%3DEqr)
![r=(KE)/Eq](https://tex.z-dn.net/?f=r%3D%28KE%29%2FEq)
#Substitute actual values in our equation:
![r=\frac{75J}{(7.2\times 10^{-5}C)(4.8\times 10^5 V/m)}\\\\=2.1701\approx2.2\ m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B75J%7D%7B%287.2%5Ctimes%2010%5E%7B-5%7DC%29%284.8%5Ctimes%2010%5E5%20V%2Fm%29%7D%5C%5C%5C%5C%3D2.1701%5Capprox2.2%5C%20m)
Hence, the distance between the charge and the source of the electric field is 2.2 meters
Explanation:
<u>Mass of car</u> = 137.5 kg
<u>Acceleration</u> = v - u / t = 26 - 0 / 6 = 4.33 m/sec^2
Force = m * a = 137.5 * 4.33 = 595.3 N
Yes because of the smoke you are creating in the air
Answer:
![F= 17,075\ N](https://tex.z-dn.net/?f=F%3D%2017%2C075%5C%20N)
Explanation:
When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.
The accelerating force can be calculated using Newton's second law:
![F=m\cdot a](https://tex.z-dn.net/?f=F%3Dm%5Ccdot%20a)
Where m is the mass of the car and a is the acceleration.
![F=3,415\ kg\cdot 5\ m/s^2](https://tex.z-dn.net/?f=F%3D3%2C415%5C%20kg%5Ccdot%205%5C%20m%2Fs%5E2)
![\boxed{F= 17,075\ N}](https://tex.z-dn.net/?f=%5Cboxed%7BF%3D%2017%2C075%5C%20N%7D)