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Diano4ka-milaya [45]
3 years ago
12

Can someone please help me with my physics?​

Physics
1 answer:
QveST [7]3 years ago
4 0

Answer:

3. A

1. B i think

5. C

Explanation:

i dont know the others

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Each cell in the battery has a potential difference of 1,5 V. calculate. the reading on the ammeter ,A​
mr_godi [17]

Answer:

0.30A

Explanation:

5 0
3 years ago
An outside force, Fo, brings two small metal spheres, A and B, at rest from a long distance away to a point where they are 1 met
Ksenya-84 [330]

Answer:

1)

The total work done by outside force is W_{o}=0.294J

2)

The total work done by the electric field is -W_{o} =-0.294J

3)

The potential energy of the two sphere system is  PE = W_{o} = 0.294J

4)

The magnitude of the acceleration of sphere A is a_{A} = 66.868m/s^2

5)

The magnitude of the acceleration of sphere B is a_{B} = 26.747 \ m/s^2

6)

The magnitude of velocity sphere A after a very long time is  v_{A} = 10.251 \ m/s\

7) The magnitude of velocity sphere B after a very long time is  v_{B} = 4.1 m/s

 

Explanation:

The explanation is shown on the first and second uploaded image

4 0
3 years ago
Which cell structure is found in plant cells, but not in animal cells?
andre [41]

Answer:

chloroplasts

Explanation:

5 0
3 years ago
Read 2 more answers
A force vector F1 points due east and has a magnitude of 200N. A second force F2 is added to F1. The resultant of the two vector
PilotLPTM [1.2K]

Answer:

The second vector \vec{F_2} points due West with a magnitude of 600N

Explanation:

The original vector \vec{F_1} points with a magnitude of 200N due east, the Resultant vector \vec{R} points due west (that's how east/west direction can be interpreted, from east to west) with a magnitude of  400N. If we choose East as the positive direction and West as the negative one, we can write the following vectorial equation:

\vec{F_1}+\vec{F_2}=\vec{R}\implies\vec{F_2}=\vec{R}-\vec{F_1}=-400N-200N=-600N

With the negative sign signifying that the vector points west.

3 0
4 years ago
A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg
Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

p_i=mv+0=mv

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

p_f=mv'+MV'

Equating initial and the final momenta we get

mv=mv'+MV'\\\\m(v-v')=MV'.....i

Now since the surface is frictionless thus the energy is also conserved thus

E_i=\frac{1}{2}mv^2

Similarly the final energy becomes

E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\

Equating initial and final energies we get

\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)

Solving i and ii we get

v+v'=V'

Using this in equation i we get

v'=\frac{v(m-M)}{(M-m)}=-v

Thus putting v = -v' in equation i  we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

4 0
3 years ago
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