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Andre45 [30]
3 years ago
13

A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg

ligible during this linear elastic collision, a)stone A will slow down but continue moving forward b) stone A will rebound and stone B will move forward c) stone a will rebound but stone b will remain stationary d) stone A will stop and stone b will move forward
Physics
1 answer:
Kitty [74]3 years ago
4 0

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

p_i=mv+0=mv

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

p_f=mv'+MV'

Equating initial and the final momenta we get

mv=mv'+MV'\\\\m(v-v')=MV'.....i

Now since the surface is frictionless thus the energy is also conserved thus

E_i=\frac{1}{2}mv^2

Similarly the final energy becomes

E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\

Equating initial and final energies we get

\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)

Solving i and ii we get

v+v'=V'

Using this in equation i we get

v'=\frac{v(m-M)}{(M-m)}=-v

Thus putting v = -v' in equation i  we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

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Answer:

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Explanation:

Work is defined by the expression

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where the boldface indicates vectors, this equation can be written in scalar form

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where θ is the angle between force and displacement.

We see that there is no dependence on speed, so the work remains constant

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3 years ago
If a body of mass 2 kg is moving with a velocity of 30 m/s, then
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Answer:

d. 60

Explanation:

If a body of mass 2 kg is moving with a velocity of 30 m/s, then

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2 years ago
A VW beetle goes from zero to 27m/s in 7.6 seconds. What is the acceleration?
Firlakuza [10]
Initial speed(u)=0m/s
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3 years ago
A disk of radius 10 cm is pulled along a frictionless surface with a force of 16 N by a string wrapped around the edge. At the i
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Answer:

t = 0.2845Nm (rounded to 4 decimal places)

Explanation:

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Radius in meters = 10/100 = 0.1m

t = 0.1m × 16N × sin160.4°

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