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Y_Kistochka [10]
4 years ago
9

The equilibrium constant for the gas phase reaction

Chemistry
1 answer:
stellarik [79]4 years ago
6 0
The equilibrium constant is found by [product]/[reactant]

If the equilibrium constant is very small, such as 4.20 * 10^-31, then that means at equilibrium there is very little product and a lot of reactant.
And likewise, if there is a lot of product formed, and very little reactant, then the K value will be very large, which tells us that it is predominantly product.

At equilibrium, for any reaction, there will always be some reactant and some product present. There cannot be zero reactant or zero product. Also keep in mind that the equilibrium constant is dependent on temperature.

At equilibrium, for your reaction, it is predominantly reactants.
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Answer:

A) homotopic and B) enantiotopic

Explanation:

Protons chemically equivalent are those that have the same chemical shift, also if they are interchangeable by some symmetry operation or by a rapid chemical process.

The existence of symmetry axes, Cn, that relate to the protons results in the protons being homotopic, that is chemically equivalent in both chiral and aquiral environments.

The existence of a plane of symmetry, σ, makes the protons related by it, are enantiotopic and these protons will only be equivalent in an aquiral medium; if the medium is chiral both protons will be chemically NOT equivalent. The existence of a center of symmetry, i, in the molecule makes the related protons through it enantiotopic and therefore chemically only in the aquiral medium.

Diastereotopic protons cannot be interconverted by any symmetry operation and they are different, with different chemical displacement.

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3 years ago
Is h2so4 a Arrhenius acid
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Answer : Yes , H2SO4 is an arrhenius acid

<h2>Explanations : </h2>

• An ,Arrhenius acid ,is a substance that ,dissociates, in water to form ,hydrogen ions (H+).

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• In other words, an arrhenius acid increases the H+ ion concentration in aqueous solution.

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• This can be represented by the equation :

H_SO_4^{-\text{ }}\rightleftarrows H^{+\text{ }}+SO_4^{2-}

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Explanation:

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