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Radda [10]
2 years ago
14

What number balances the equations?!

Chemistry
1 answer:
Maru [420]2 years ago
3 0

Answer:

2

Explanation:

your answer is correct. The overall balanced equation would be:

2Cu +2HNO3 ----> 2CuNO3 +H2

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Three reasons for air is mixture and water is compound
zhannawk [14.2K]
1. air components change from place to place, while water will just stay the same

2. Water doesn't have nor show individual properties, but air does show that it has it's own property

3. You can separate different gases from air physically, but with water you must pass electricity through it.

Don't take my word for it, this is just what I learned back in middle school. 
8 0
3 years ago
Read 2 more answers
Determine the oxidation number for nitrogenin
iris [78.8K]

Answer:

1(a) N = 3

(b) N = 0

(c) N = 5

(d) N = -2

(2) Molecular formula for benzene is C6H6

Explanation:

1(a) N02 1-

N + (2×-2) = -1

N-4 = -1

N = -1+4 = 3

(b) N2

2(N) = 0

N = 0/2 = 0

(c) NO2Cl

N + ( 2×-2) + (-1) = 0

N - 4 - 1 = 0

N - 5 = 0

N = 0+5 = 5

(d) N2H4

2(N) + (4×1) = 0

2N + 4 = 0

2N = 0 - 4 = -4

N = -4/2 = -2

(2) Molcular mass of benzene = 78g/mole = (6×12g of carbon) + (6×1g of hydrogen) = 72+6 = 78g/mole

Therefore, molecular formula for benzene is C6H6

7 0
3 years ago
Which chemical equation below is balanced to follow the Law of Conservation of Mass?
vekshin1

Answer:

Balanced Equation

H₂ + Cl₂ → 2HCI

3 0
3 years ago
Read 2 more answers
How many atoms are in an oxygen molecule?
ZanzabumX [31]

Answer:

two atoms

Explanation:

In its stable molecular form, oxygen exists as two atoms and is written O2. to distinguish it from an atom of oxygen O, or ozone, a molecule of three oxygen atoms, O3. Even though each of these is all oxygen, combining atoms of the same element may give very different properties to the molecule.

6 0
3 years ago
a chemistry teacher adds 50.0 ml of 1.50 m h2so4 solution to 200 ml of water. What is the concentration of the final solution?
nevsk [136]

Answer:0.300M

Explanation:1) Data:

a) Initial solution

M = 1.50M

V = 50.0 ml = 0.050 l

b) Solvent added = 200 ml = 0.200 l

2) Formula:

Molarity: M = moles of solute / volume of solution is liters

3) Solution:

a) initial solution:

Clearing moles from the molarity formula: moles = M × V

moles of H₂SO₄ = M × V = 1.5M × 0.050 l = 0.075 mol

b) final solution:

i) Volumen of solution = 0.050 l + 0.200l = 0.250l

ii) M = 0.075 mol / 0.250 l = 0.300M ← answeer

5 0
3 years ago
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