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babunello [35]
2 years ago
8

If a plant grows among many tall trees in a dense forest,how could it adapt so that it could get enough air and water

Physics
1 answer:
Nadusha1986 [10]2 years ago
4 0

Answer:

The answer is below

Explanation:

Plants that grow among many tall trees in a dense forest could adapt so that they could get enough air and water through the following means:

1. By becoming climbers. Here they climb up the nearby trees to get more air and sunlight.

2. Plants grow leaves that have pointed tips. This allows the passage of water in the plant's leaves without causing damage.

3. Some plants grow as epiphytes, where they grow on big trees' canopy

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IMA = Ideal Mechanical Advantage

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Where F1 is the force applied to beat F2. The distance from F1 and the pivot is x1 and the distance from F2 and the pivot is x2

=> F1/F2 = x1 /x2

IMA = F1/F2 = x1/x2

Now you can see the effects of changing F1, F2, x1 and x2.

If you decrease the lengt X1 between the applied effort (F1) and the pivot,  IMA decreases.

If you increase the length X1 between the applied effort (F1) and the pivot, IMA increases.

If you decrease the applied effort (F1) and increase the distance between it and the pivot (X1) the new IMA may incrase or decrase depending on the ratio of the changes.

If you decrease the applied effort (F1) and decrease the distance between it and the pivot  (X1) IMA will decrease.

Answer: Increase the length between the applied effort and the pivot.
4 0
3 years ago
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How do you calculate the magnitude of the resultant force of two
zlopas [31]

Answer:

Two forces that act in opposite directions produce a resultant force that is smaller than either individual force. To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force.

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A nonconducting spherical shell, with an inner radius of 4 cm and an outer radius of 6 cm, has charge spread non uniformly throu
Aloiza [94]
In other words a infinitesimal segment dV caries the charge 
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<span>Let dV be a spherical shell between between r and (r + dr): </span>
<span>dV = (4π/3)·( (r + dr)² - r³ ) </span>
<span>= (4π/3)·( r³ + 3·r²·dr + 3·r·(dr)² + /dr)³ - r³ ) </span>
<span>= (4π/3)·( 3·r²·dr + 3·r·(dr)² + /dr)³ ) </span>
<span>drop higher order terms </span>
<span>= 4·π·r²·dr </span>

<span>To get total charge integrate over the whole volume of your object, i.e. </span>
<span>from ri to ra: </span>
<span>Q = ∫ dQ = ∫ ρ dV </span>
<span>= ∫ri→ra { (b/r)·4·π·r² } dr </span>
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<span>With given parameters: </span>
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6 0
3 years ago
I need a short written description of Newton's three laws.
Tom [10]
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3 years ago
When Simon grows (let’s say he doubles his mass) what happens to his GPE when he is at the balcony?
DerKrebs [107]

Answer:

His gravitational potential energy will increase as well.

Explanation:

Let gpe represent gravitational potential energy.

gpe = mass × gravitational field strength × height

From the formula above, we can conclude that as the mass of a body increases, it's gpe increases too.

5 0
2 years ago
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