All categories

2 years ago

If a plant grows among many tall trees in a dense forest,how could it adapt so that it could get enough air and water

Physics

1 answer:

Nadusha1986 [10]2 years ago

4 0

Answer:

The answer is below

Explanation:

Plants that grow among many tall trees in a dense forest could adapt so that they could get enough air and water through the following means:

1. By becoming climbers. Here they climb up the nearby trees to get more air and sunlight.

2. Plants grow leaves that have pointed tips. This allows the passage of water in the plant's leaves without causing damage.

3. Some plants grow as epiphytes, where they grow on big trees' canopy

You might be interested in

Automobiles must be able to sustain a frontal impacl The automobile design must allow low speed impacts with little sustained da

valentinak56 [21]

Answer: the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

Explanation:

Given that;

mass of vehicle m = 1000 kg

for a low speed test; V = 2.5 m/s

bumper maximum deflection = 4 cm = 0.04 m

First we determine the energy of the vehicle just prior to impact;

W_v = 1/2mv²

we substitute

W_v = 1/2 × 1000 × (2.5)²

W_v = 3125 J

now, the the effective design stiffness k will be:

at the impact point, energy of the vehicle converts to elastic potential energy of the bumper;

hence;

W_v = 1/2kx²

we substitute

3125 = 1/2 × k (0.04)²

3125 = 0.0008k

k = 3125 / 0.0008

k = 3906250 N/m

Therefore, the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

3 0

2 years ago

Plsss hlppppppp!!!!!!!!!!!!!

masya89 [10]

Explanation:

The angular momentum is doubled because it is proportional to the angular velocity.

6 0

1 year ago

A uniform, spherical, 1900.0 kg shell has a radius of 5.00 m. Find the gravitational force this shell exerts on a 1.80 kg point

Mandarinka [93]

Answer:

$F=9.09\times 10^{-9} N$

Explanation:

We are given that

Mass of spherical shell, $m_1$ =1900 kg

Mass= $m_2=1.80 kg$

Radius of shell=r=5 m

Distance between two masses=r=5.01 m

Because distance measure from center .

Gravitational force

$F=G\frac{m_1m_2}{r^2}$

$G=6.67\times 10^{-11} Nm^2/kg^2$

Using the formula

$F=6.67\times 10^{-11}\times \frac{1900\times 1.80}{(5.01)^2}$

$F=9.09\times 10^{-9} N$

Hence,the gravitational force = $F=9.09\times 10^{-9} N$

6 0

2 years ago

So, like my previous question, how do you solve for 4/5 - 1/2?

ZanzabumX [31]

Answer:

3/10

Explanation:

4/5(2)

-1/2(5)

8/10-5/10

3/10

6 0

2 years ago

Read 2 more answers

A soccer player kicks a ball horizontally at 28 m/s from a bridge and hits the ground after 1.5 s. What is the range of the ball

Lelu [443]

Answer:

Explanation:

range of ball = u×t

= 28×1.5

=42

8 0

2 years ago