Solution here,
Volume(V)=67.4 L
Pressure(P)=1 atm
Temperature(T)=(0+273)K=273K
Universal gas constant(R)=0.0821 L.atm.mol^-1K^-1
No. of moles(n)=?
Now,
PV=nRT
or, 1×67.4=n×0.0821×273
or, 67.4=22.4n
or, n=67.4/22.4
or, n=3
therefore, required no. of mole is 3.
Answer:
Molar Mass: 138.9818 g/mol
Explanation:
Answer:
86.735 kJ
Explanation:
Simply multiply the change in temperature by the Ccal;
(36.6 - 20.0)×5.225 = 86.735
