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4 years ago

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Chemistry

1 answer:

ycow [4]4 years ago

8 0

I think it is True. If not I am sorry. Best of luck to you and ur test! :)

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Lysosomes break down old and worn-out cell parts.

Veseljchak [2.6K]

Explanation:

it's true that Lysosomes break down old and worn out cell parts....

3 0

3 years ago

True or false? The empirical formula of a compound is the simplest formula that shows the numerical relationship of the elements

Delicious77 [7]

Answer:

True

Explanation:

I think it’s true because the empirical formula of a compound is actually the simplest formula that shows the numerical relationship of the elements in the compound.

hop that helps!

7 0

3 years ago

Read 2 more answers

Consider the reaction below in a closed flask. At 200 o C, the equilibrium constant (Kp) is 2.40 × 103 . 2 NO (g)  N2 (g) + O2

olga55 [171]

Explanation:

Since, the given reaction is as follows.

$2NO(g) \rightleftharpoons N_{2}(g) + O_{2}(g)$

Initial: 36.1 atm 0 0

Change: 2x x x

Equilibrium: (36.1 - 2x) x x

Now, expression for $K_{p}$ of this reaction is as follows.

$K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}$

As the initial pressure of NO is 36.1 atm. Hence, partial pressure of $O_{2}$ at equilibrium will be calculated as follows.

$K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}$

$2.40 \times 10^{3} = \frac{x \times x}{(36.1 - 2x)^{2}}$

x = 18.1 atm

Thus, we can conclude that partial pressure of $O_{2}$ at equilibrium is 18.1 atm.

5 0

3 years ago

Read 2 more answers

An example of gas dissolved into water would be soda. True False

denis-greek [22]

Answer:

It would be true cause the example of gas would be coke soda

Explanation:

4 0

2 years ago

Add coefficients to the reaction summary to show the net results of glycolysis. glucose+a ADP+b Pi+c NAD+⟶x pyruvate+y ATP+z NAD

Katyanochek1 [597]

Answer:

See figure 1

Explanation:

For this question, we can start with the structure of pyruvic acid. In this molecule, we have two functional groups, the ketone group, and a carboxylic acid group.

In the acid group, we have an acidic hydrogen. That is, this hydrogen can leave the molecule to produce a hydronium ion ( $H^+$ ).

Now, to know what is the pH at which this hydrogen leaves the molecule we must look for the pKa value. Which for the case of this molecule is 2.45

If there is a pH value greater than 2.45, the molecule will lose hydrogen. In this case, we will have a value above 2.45 (7.4), which is why the conjugated acid of pyruvic acid will be produced, which is pyruvate.

Therefore, in the structure, we will have a negative charge on the acid group.

See figure 1

I hope it helps!

3 0

4 years ago