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3 years ago

Please answer I will give good rating and mark brainlest

Physics

1 answer:

lina2011 [118]3 years ago

8 0

The answer is C. You must divide your wavelength and your frequency to get your answer.

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WILL MARK BRAIN<br> A=154<br> B=145<br> C=26<br> D=206

ANEK [815]

Answer:

154

Explanation:

5 0

3 years ago

A car starting from rest accelerates at a constant 2.0 m/s2 for 10 s. It then travels with constant speed it has achieved for an

Anon25 [30]

Answer:

The total distance will be 400 m.

Explanation:

For portion AB:

Acceleration = 2 $m/s^2$

t= 10 s

Car start from rest , u=0 m/s

We know that

$S=ut+\dfrac{1}{2}at^2$

$S=0+\dfrac{1}{2}\times 2\times 10^2$

S= 100 m.

For portion BC:

V= u + at

V=0 + 2 x 10

V= 20 m/s

In this portion car moves with constant velocity 20 m/s for 10 s.

So distance S= V x t

S=20 x 10 =200 m.

For portion CD:

The velocity at point C will be 20 m/s

In this portion the final speed of car will be zero because given that at final car come to rest.

So the acceleration will be in the negative direction to stop the car.

We know that

$v^2=u^2-2aS$

$0=20^2-2\times 2\times S$

S=100 m

The total distance AD=AB + BC+ CD

AD=100 +200 + 100 m

AD=400 m.

The total distance will be 400 m.

4 0

3 years ago

Do you think most Americans are in good psychological health?

bekas [8.4K]

Answer:

Honestly, as an American, they really aren't. Considering what's been happening in recent years with school shootings and su*cide rates rising.

5 0

3 years ago

Read 2 more answers

A pickup truck is carrying a toolbox, but the rear gate of the truck is missing, so the box will slide out if it is set moving.

Anon25 [30]

Answer:

t=7.33 s

Explanation:

According to Newton's second law:

$\sum F=m*a$

because we don't want the box to slide, the acceleration has to be zero.

$\sum F=-F_{friction}+F_{truck}=0\\F_{truck}=F_{friction}\\F_{friction}=\µ*m*g=0.500*9.81*m\\F_{friction}=4.91*m$

we know that:

$F=m*a\\4.91m=m*a\\a=4.91m/s^2$

Now having the acceleration, we can use the following formula.

$v_f=a*t\\t=\frac{36.0m/s}{4.91m/s^2}\\\\t=7.33s$

7 0

3 years ago

PLEASE HELP

Sergeu [11.5K]

The vertical component of the initial velocity is $v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is $v_0_x = \frac{x}{t}$

The horizontal displacement when the object reaches maximum height is $X = \frac{xy}{gt^2} + \frac{x}{2}$

The given parameters;

the horizontal displacement of the object, = x

the vertical displacement of the object, = y

acceleration due to gravity, = g

time of motion, = t

The vertical component of the initial velocity is given as;

$y = v_0_yt - \frac{1}{2} gt^2\\\\v_0_yt = y + \frac{1}{2} gt^2\\\\v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is calculated as;

$x = v_0_xt\\\\v_0_x = \frac{x}{t}$

The time to reach to the maximum height is calculated as;

$T = \frac{v_f_y -v_0_y}{-g} \\\\T = \frac{-v_0_y}{-g} \\\\T = \frac{v_0_y}{g} \\\\T = \frac{1}{g} (v_0_y)\\\\T = \frac{1}{g} (\frac{y}{t} + \frac{1}{2} gt)\\\\T = \frac{y}{gt} + \frac{1}{2} t$

The horizontal displacement when the object reaches maximum height is calculated as;

$X= v_0_x \times T\\\\X= \frac{x}{t} \times (\frac{y}{gt} + \frac{1}{2} t)\\\\X = \frac{xy}{gt^2} + \frac{x}{2}$

Learn more here: brainly.com/question/20689870

8 0

3 years ago