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Katyanochek1 [597]
4 years ago
12

You are driving at 75 km/h. Your sister follows in the car behind at 75 km/h. When you honk your horn, your sister hears a frequ

ency You are driving at 75 . Your sister follows in the car behind at 75 . When you honk your horn, your sister hears a frequency lower than the frequency you hear. higher than the frequency you hear. the same as the frequency you hear. You cannot tell without knowing the horn's frequency.
Physics
1 answer:
OLga [1]4 years ago
5 0

The ideal concept for solving this question is based on the Doppler effect, for which it is indicated that the source's listening frequency changes as the distance and the relative speed between the receiver and the transmitter are also changed. However, if the relative velocity between the two objects is zero as in the particular case presented (since both travel at 75km / h) we have that there will be no change in frequency.

Therefore the frequency that I hear and that my sister would listen would be the same.

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sound travels through a medium in mechanical waves a mechanical wave is a disturbance that moves and transports energy from one place to another through a medium

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3 years ago
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6 0
3 years ago
A wave with a greater amplitude will transfer . . . . \
Orlov [11]

Answer:

More energy

Explanation:

The amount of energy carried by a wave is related to the amplitude of the wave itself. In particular, the amount of energy carried by the wave is proportional to the square of the amplitude of the wave:

E \propto A^2

where

E is the energy

A is the amplitude

This means, for instance, that if the amplitude of a wave is doubled, the energy it carries increases by a factor 4.

8 0
3 years ago
A 1056-hertz tuning fork is struck at the same time as a note on the piano and you hear 2 beats/second. You tighten the piano st
elena-14-01-66 [18.8K]

Answer:

The frequency of the piano string is <em>1059 Hz</em>.

Explanation:

The frequency beat (fb), 2 beats/second, is the absolute difference between the frequency of the tuning fork (1056 Hz) and the frequency of the piano string.

As the piano string gets tightened, the frequency beat becomes 3 beats/second.

Therefore,

fb = fb = fpiano - ftuning fork\\ 3 Hz=fpiano-1056Hz\\ fpiano=1056Hz+3Hz\\ fpiano=1059Hz

6 0
3 years ago
If an oscillating mass has a frequency of 1.25 Hz, it makes 100 oscillations in
KatRina [158]

Answer:

Time, t = 80 seconds

Explanation:

Given that,

The frequency of the oscillating mass, f = 1.25 Hz

Number of oscillations, n = 100

We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :

f=\dfrac{n}{t}

t=\dfrac{n}{f}

t=\dfrac{100}{1.25\ Hz}

t = 80 seconds

So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.

4 0
3 years ago
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