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Firdavs [7]
3 years ago
14

A cheetah runs with a constant speed of 8 m/s. How far has the cheetah gone after 25 seconds?

Physics
2 answers:
Radda [10]3 years ago
7 0
Multiply 25 * 8 = 200
So the cheetah has gone 200 miles in 25 seconds
Rom4ik [11]3 years ago
5 0
200 meters.

In one second, a cheetah runs 8m/s, so multiply 8 by 25.

8 x 25 = 200
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How many nanoseconds does it take light to travel 3.50 ft in vacuum?
Fiesta28 [93]
Answer:3.56 nanosecond

In this case, you are asked the time and given the light distance(3.5ft)
To answer this question you would need to know the velocity of light. Speed of light is <span>299792458m/s. Then the calculation would be:

time= distance/speed
time= 3.5 ft / (</span>299792458m/s) x 0.3048 meter/ 1 ft=  3.56 10^{-9} second or 3.56 nanosecond
6 0
3 years ago
Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, spee
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Answer:

Light slows down when it moves from air into water.

Explanation:

It is the property of light that travels faster in a less dense medium.

In a more dense medium, the speed of the light slows down and bends towards the normal.

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When light passes from air to water, the light bends.

This is known as the refraction of light.

4 0
3 years ago
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1. Any push or pull is called
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b  ok

Explanation:

7 0
3 years ago
The diagram shows the Earth rotating on it's axis. The two stars show different locations on the surface... How long does it tak
amid [387]
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6 0
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A satellite is in a circular orbit 21000 km above the Earth’s surface; i.e., it moves on a circular path under the influence of
mina [271]

Answer:

(orbital speed of the satellite) V₀ = 3.818 km

Time (t) = 4.5 × 10⁴s

Explanation:

Given that:

The radius of the Earth is 6.37 × 10⁶ m;    &

the acceleration of gravity at the satellite’s altitude is 0.532655 m/s

We can calculate the orbital speed of the satellite by using the formula:

Orbital Speed (V₀) = √(r × g)

radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m

                                  = (2.1 × 10⁷ + 6.37 × 10⁶) m

                                  = 27370000

                                  = 2.737 × 10⁷m

Orbital Speed (V₀) = √(r × g)

Orbital Speed (V₀) = √(2.737 × 10⁷  × 0.532655 )

                              = 3818.215

                              = 3.818 × 10³

                             = 3.818 Km

To find the time it takes to complete one orbit around the Earth; we use the formula:

Time (t) = 2 π × \frac{r}{V_o}

            = 2 × 3.14 × \frac{2.737*10^7}{3.818*10^3}

            = 45019.28

            = 4.5 × 10 ⁴ s

6 0
3 years ago
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