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IgorLugansk [536]
3 years ago
15

Read each scenario and then answer the question scenario a 120 J of work is done in 6 seconds Scenario b 160 J of work is done i

n 8 seconds scenario c 200 J of work is done in 10 seconds which scenario uses the most power
Physics
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

all scenarios are using the same power

Explanation:

we know that power is defined as P(Watts)=W(Joules)/t(seconds).

When applying this formula to each of the scenarios we find:

\frac{120J}{6s}=\frac{160J}{8s}=\frac{200J}{10s}= 20W

Done

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A straight fin is made from copper (k = 388 W/m-K) and is 0.5 cm in diameter and 30 cm long. The temperature at the base of the
erastovalidia [21]

Answer:

The rate of transfer of heat is 0.119 W

Solution:

As per the question:

Diameter of the fin, D = 0.5 cm = 0.005 m

Length of the fin, l =30 cm = 0.3 m

Base temperature, T_{b} = 75^{\circ}C

Air temperature, T_{infty} = 20^{\circ}

k = 388 W/mK

h = 20\ W/m^{2}K

Now,

Perimeter of the fin, p = \pi D = 0.005\pi \ m

Cross-sectional area of the fin, A = \frac{\pi}{4}D^{2}

A = \frac{\pi}{4}(0.5\times 10^{-2})^{2} = 6.25\times 10^{- 6}\pi \ m^{2}

To calculate the heat transfer rate:

Q_{f} = \sqrt{hkpA}tanh(ml)(T_{b} - T_{infty})

where

m = \sqrt{\frac{hp}{kA}} = \sqrt{\frac{20\times 0.005\pi}{388\times 6.25\times 10^{- 6}\pi}} = 41.237

Now,

Q_{f} = \sqrt{20\times 388\times 0.005\pi\times 6.25\times 10^{- 6}\pi}tanh(41.237\times 0.3)(75 - 20) = 0.119\ W

5 0
3 years ago
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Answer:

From the negative to the positive cable.

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B. Kinetic energy is created

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M.A. = 400/40

M.A. = 10

Hope this helps!
7 0
3 years ago
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