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marusya05 [52]
3 years ago
7

Which compound is an unsaturated hydrocarbon

Chemistry
2 answers:
IceJOKER [234]3 years ago
5 0

Answer:

ethyne.

Explanation:

Oxana [17]3 years ago
3 0
Ethyne because Ch4 is the most common, and the alkalies are a part of unsaturated hydrocarbon
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While out on a hike, you find an unknown mineral. How would you test the mineral to find out what it is?
Mashcka [7]
Probably look up the descriptions of the element and see if it matches the mineral.
5 0
3 years ago
(marking brainliest!) could someone please help me with these mcqs :/​
Shalnov [3]
1. Is a (primary)
2. Is 2 (c)
3. Not sure sorry ✨
4. HBr (b)
5 0
3 years ago
A solid piece of aluminum (51.0 g) was added to a solution of sodium hydroxide (84.1 g) in water, A balanced equation for this r
EastWind [94]
M_{Al}=26,98\frac{g}{mol}\\
m=51g\\\\
n=\frac{m}{M_{Al}}=\frac{51g}{26,97\frac{g}{mol}}\approx1,89mol\\\\\\
M_{NaOH}=39,4\frac{g}{mol}\\
m=84,1g\\\\
n=\frac{m}{M_{NaOH}}=\frac{84,1g}{39,4\frac{g}{mol}}\approx2,14mol

<span>2 NaOH(aq)+ 2 Al(s)+ 2 H</span>₂<span>O → 2 NaAlO</span>₂<span>(aq)+ 3 H</span>₂<span>(g)
</span>  2mol      :     2mol           :                                  3mol
2,14mol   :     1,89mol      :                                  2,835mol
remains         completely consumed
2,14-1,89=0,25mol


A) Al

B)  

M_{NaOH}=39,4\frac{g}{mol}\\&#10;n=0,25mol \Rightarrow \ \ \ m=n*M_{NaOH}=0,25mol*39,4\frac{g}{mol}=9,85g

C)
n=2,835mol\\&#10;M_{H_{2}}=2,02\frac{g}{mol} \Rightarrow \ \ \ m=n*M_{H_{2}}=2,835mol*2,02\frac{g}{mol} \approx 5,73g

7 0
3 years ago
Using a spectrophotometer, and a cuvette with a path length of 1 cm you measure the absorbance (A275) of Guanosine to be 0.70. C
Anton [14]

Answer : The concentration of guanosine in your sample is, 8.33\times 10^{-5}M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution  = 0.70

C = concentration of solution = ?

l = path length = 1.00 cm

\epsilon = molar absorptivity coefficient guanosine  = 8400M^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

0.70=8400M^{-1}cm^{-1}\times C\times 1.00cm

C=8.33\times 10^{-5}M

Thus, the concentration of guanosine in your sample is, 8.33\times 10^{-5}M

5 0
3 years ago
What is potential energy?
Vlad [161]

Answer:

B

Explanation:

it is the energy stored in the chemical bonds of a substance

4 0
2 years ago
Read 2 more answers
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