By Newton's second law, we have
So, in order to give a 0.15kg body an acceleration of 40m/s^2, you need a force of
About how long does a cumulus cloud last?
1 answer:
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Answer:
°C
Explanation:
Given:
mass of hiker, m= 63 kg
height to be climbed, h= 828 m
energy produced by an energy bar,
heat capacity of the hiker,
initial body temperature of hiker,
<em>The efficiency of converting the energy content of the bars into the work of climbing is 25%, the remaining 75% of the energy released through metabolism is heat released to her body.</em>
We find the energy required for climbing 828 m height:
W=m.g.h
W= 511207.2 J
∵Hike eats 2 energy bars=
Energy produced
Now, according to her efficiency:
Total energy required for producing the work of W= 511207.2 J which is required to climb the given height will be (say, E):
&
Amount of total energy (E) converted into heat(Q) is:
As we know that:
heat, .................(1)
where:
is the final temperature
Putting respective values in the eq. (1)
°C