1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STALIN [3.7K]
3 years ago
12

How long would it take for a car to travel 200 km if it has an average speed of 55 km hr?

Physics
1 answer:
Rainbow [258]3 years ago
6 0

Answer:

3.63 hours or 3 and 37.5 minutes

Explanation:

200/55

Hope this helps :)

You might be interested in
Plants and trees grow nearly everywhere. this is one of the advantages of what energy?
AnnyKZ [126]

The answer is Biomass.

Letter :D

4 0
2 years ago
Read 2 more answers
Flywheels are large, massive wheels used to store energy. They can be spun up slowly, then the wheel's energy can be released qu
Kruka [31]

Answer: a) 1766 sec. b) 55.5 MJ c) 13.9 MW d) -12,944 Nm

Explanation:

a) The torque and  the angular acceleration, are related by the following expression, which resembles very much to the Newton's 2nd Law for point masses:

ζ = I . γ, where ζ=external torque, I = rotational inertia and γ = angular acceleration.

We also know that a flywheel is a solid disk, so the rotational inertia for this type of body is equal to MR² / 2.

By definition, angular acceleration is the rate of change of angular velocity with time, so we can write the following:

γ = ωf -ω₀ / t

Assuming that the flywhel starts from rest, we know that ω₀ = 0, and ωf = 12,000 rpm.

As all the units are given in SI units, it is advisable to convert the rpm to rad/sec, as follows:

12,000 rpm = 12,000 rev. (2π/rev) . (1min/60 sec) = 400 π rad/sec

Returning to the original equation, we have:

ζ = MR² / 2 . (ωf/ t)

Replacing by the values, and solving for t, we have:

t = 250 Kg. (0.75)² m² . 400 π / 2. 50 Nm = 1,766 sec.

b) Due to the flywheel is just rotating, all the stored energy is rotational kinetic energy, which can be written as follows:

K = 1/2 I ωf² = 1/2 (MR²/2) ωf² = 1/4. 250 Kg. (0.75)² m². (400π)²

K= 55.5 MJ

c) Power is defined as energy delivered in a given time.

The energy delivered, is just the half of the originally stored value, i.e. , 55.5 MJ /2, equal to 27.75 MJ.

Dividing this value by 2.0 sec, we have the average power delivered to the machine, that we found to be equal to 27.75 MJ / 2s =  13. 9 MW

d) Using the same relationship than in a), we can write the following:

ζ = I. γ

I remains the same (as the flywheel is the same), so the only unknown is the angular acceleration.

Angular acceleration, by definition, is as follows:

γ = ωf - ω₀ / t

We know the value of ω₀, as it is the top speed value that we have already got,i.e., 400 π rad/sec.

We don't know the value for ωf, but we know the value of the rotational kinetic energy after 2.0 secs, which is equal to the half of the one we obtained in step b).

So, we can write the following:

Kf = 1/2 I ωf² = 1/2 (1/2 I ω₀²) ⇒ 1/ 2 ωf² = 1/4 ω₀² ⇒ωf = ω₀/√2

Replacing in the expression for angular acceleration:

γ = (ω₀/√2 - ω₀) / t = -0.29. 400. π/ 2 rad/sec²= -184.1 rad/sec²

Finally, we can get the torque as follows:

ζ = (250 kg. (0.75)² m² /2) . 184.1 rad/sec² = -12,944 Nm

6 0
3 years ago
Se lanza una piedra de 3.00 N verticalmente hacia arriba desde el suelo. Se observa que, cuando está 15.0 m sobre el suelo, viaj
BARSIC [14]

Answer:

(a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Explanation:

Given that,

Weight of stone = 3.00 N

Height = 15 m

Speed = 25.0 m/s

(a). We need to calculate the speed at the moment of being thrown

Using work energy theorem

W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

Put the value into the formula

-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)

-2\times9.8\times15=25^2-v_{1}^2

-v_{1}^2=-300-25^2

v_{1}=\sqrt{925}

v_{1}=30.41\ m/s

(b). We need to calculate the maximum height

Using work energy theorem

[tex]W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2

mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2

Here, \dfrac{1}{2}mv_{2}^2=0

-(mg)\times d=\dfrac{1}{2}mv_{1}^2

d=\dfrac{v_{1}^2}{2g}

Put the value into the formula

d=\dfrac{30.41^2}{2\times9.8}

d=47.18\ m

Hence, (a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

6 0
2 years ago
How much energy (in kW-h) does a 900 Watt stove use in a week if it is used for 1.5 hours each day?
ioda

Answer:

9.45 kWh

Explanation:

Energy = Power × time

E = 900 W × (1.5 h/day × 7 day)

E = 9450 Wh

E = 9.45 kWh

3 0
3 years ago
Reggie can do 50 pushups in one minute. If the mass that Reggie is lifting which each push-up is at 92 kg, what must also be mea
Sergio039 [100]
The missing measurement is distance.
8 0
3 years ago
Other questions:
  • If I push on a wall with a force of 3500 N for 5 hours but the wall does not move, how much work have I done.
    9·1 answer
  • What needs to be done to this circuit so that the light bulb lights up?
    11·2 answers
  • I
    7·1 answer
  • Does a break in one branch affect another branch in a parallel circuit
    12·1 answer
  • According to Newton's Universal Law of Gravitation, when the distance between two interacting objects doubles, the gravitational
    14·1 answer
  • A diver 50 m deep in 10∘C fresh water exhales a 1.0-cm-diameter bubble. What is the bubble's diameter just as it reaches the sur
    7·1 answer
  • Work, Power, and Energy
    10·1 answer
  • A pendulum consists of a weight tied by a string that is attached to the ceiling. The diagram models the motion of the pendulum
    9·1 answer
  • I drew a doggy but ima show you guys the other ones tommorow cause im still drawing
    15·2 answers
  • A motorboat starting from rest travels in a straight line on a lake. If the boat reahes a speed of 8.0m/s in 10s what is the boa
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!