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grin007 [14]
4 years ago
15

What mechanism is most responsible for generating the internal heat of Io that drives its volcanic activity?

Physics
1 answer:
Ghella [55]4 years ago
8 0

Answer:

Tidal heating

Explanation:

Tidal force is the ability of a massive body to produce tides on another body. The tidal force depends on the mass of the body that produces the tides and the distance between the two bodies.

Tidal forces can cause the destruction of a satellite that orbits a planet or a comet that is too close to the Sun or a planet. When the orbiting body crosses the "Roche boundary", the tidal forces along the body are more intense than the cohesion forces that hold the body together.

Tidal friction is the force between the Earth's oceans and ocean floors caused by the gravitational attraction of the Moon. The Earth tries to transport the waters of the oceans with it, while the Moon tries to keep them under it and on the opposite side of the Earth. In the long term, tidal friction causes the Earth's rotation speed to decrease, thus shortening the day. In turn, the Moon increases its angular momentum and gradually spirals away from Earth. Finally, when the day equals the orbital period of the Moon (which will be about 40 times the length of the current day), the process will cease. Subsequently, a new process will begin when the power to raise tides from the Sun takes angular momentum from the Earth-Moon system. The Moon will then spiral towards Earth until it is destroyed when it enters the "Roche boundary."

<u>Tidal heating </u>

It is the warming caused by the tidal action on a planet or satellite. The most important example of tidal heating in the Solar System is the effect of Jupiter on its Io satellite, in which the tidal effects produce such high temperatures that the interior of the satellite melts, producing volcanism.

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3 years ago
Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat's position is &lt; 2, 0, 3 &gt; m and its speed is
liraira [26]

Answer:

(a) work done by Jack is -2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position =  < 2, 0, 3 > m

Final boat's position = < 6, 0, 1 > m

change in position = < 4, 0, -2 >

Force exerted by Jack =  < -440, 0, 220 > N

Force exerted by Jill = < 170, 0, 340 > N

Part (a) How much work does Jack do?

work done = force x distance

Jack's work = < -440, 0, 220 > N x < 4, 0, -2 > m

                    = [(-440*4) + (0*0) + (220*-2)]

                    = -1760 J - 440 J

                    = -2200J

Part (b) How much work does Jill do?

Jill's work = < 170, 0, 340 > N x < 4, 0, -2> m

                 = [(170*4) + (0*0) + (340*-2)]

                  = 680 J - 680 J

                   = 0

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