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OverLord2011 [107]
3 years ago
12

The wattage of a bulb is 24 W when it is connected to a 12 V battery. Calculate its effective wattage if it operates on a 6 V ba

ttery.
Physics
2 answers:
posledela3 years ago
4 0

The power dissipated by a resistance ' R '
powered by a battery ' V ' is                            
                                                 P = V² / R .

Before we play with actual numbers, look at that formula, and
notice that the power is proportional to the square of the voltage. 
So if the voltage suddenly drops by half, then the power that's
dissipated by the resistance drops to 1/2² = 1/4 of where it started out.

Now that we have the pure Science worked out, we're ready to do
the Engineering, and apply our findings to some actual technology.

We have a light bulb that's designed to dissipate energy at the rate
of 24W when you connect it to a source of 12V .  But all we have
in the lab today is a 6V battery.  What power will our bulb dissipate
if we connect it to the 6V that we have, instead of the 12V that it's
designed for ?

We're all standing around scratching our beards, when the new hot-shot
post-doc lab assistant reminds us of the formula up in the first paragraph,
and shows us that since we're running it at 1/2 of the design voltage, we
expect it to dissipate 1/4 of design power = 6 watts.

It'll give us a bit of light so we can still walk around the lab without bumping
into things, but it won't get hot enough to warm our lunches.  We'll have to
do that over a Bunsen burner or in the microwave oven today, and one of
you junior members of the lab staff will have to stop at Lady-o'-Rack and
pick up either a new battery or a new bulb on your way in to work tomorrow.
tresset_1 [31]3 years ago
3 0
It would be 12W because: 6v is half of 12v so half of 24w would be 12w
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Heat pumps move heat from __________ to __________ areas & REQUIRES energy. *
sergejj [24]
The correct answer to this question is false
8 0
3 years ago
Why do we call the microscope a compound light microscope
Ede4ka [16]

Explanation:

Types of light microscope

1. Compound , and 2. Stereo Microscope

Compound microscope has two lens system also called compound lens system. The objective lens and the eyepiece lens. The magnification provided by the objective lens is compounded by the eyepiece lens, the a higher magnification is observed.

6 0
3 years ago
Can someone answer all of the questions?
Katyanochek1 [597]

Answer: -200

Explanation: is it math

8 0
2 years ago
Read 2 more answers
2. Three super strong teenagers pull a heavy crate across the floor. Dion pulls with a force of 18.5 N towards 0°. Shirley pulls
kogti [31]

Answer:

A) The resultant force is 43.4 [N]

B) The movement of the heavy crate is going to the right and in the negative direction on the y-axis

Explanation:

We need to make a sketch of the different forces acting on the heavy crate.

In the attached image we can see the forces and the sum of the vector with their respective angles.

Forces in the X-axis

Fdionx=18.5N\\\\Fshix=16.5*cos(30)=14.29N\\Fjoanx=19.5*cos(60)=9.75N\\\\Forcex= 18.5 + 14.29 + 9.75 = 42.54 N

Forces in the y-axis

FDiony=0[N]\\Fshirley= 16.5*sin(30)=8.25[N]\\Fjoany=19.5*sin(60)=16.88 [N]\\\\Forcesy=0+8.25-16.88= -8.63[N]

Using the Pythagorean theorem

Tforce=\sqrt{(42.54)^{2} +(8.63)^{2} } \\\\Tforce= 43.4N

The movement of the heavy crate is going to the right and in the negative direction on the y-axis, this can be easily seen in the graphical sum of vectors.

8 0
3 years ago
Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
pochemuha

Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

Area of the rectangle = 3.5504mm²

The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

Area of the rectangle = 3.6mm² (to 2sf)

For statement B;

Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.

Area of the rectangle = 2.536mm * 1.41mm

Area of the rectangle = 3.57576mm²

Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.

Area of the rectangle = 3.58mm² (to 3sf)

Based on the conversion, it can be seen that 3.6mm²  is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.

7 0
3 years ago
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