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jolli1 [7]
3 years ago
9

CAN SOMEONE PLEASE DO THIS FOR ME. ILL GIVE YOU BRAINLIEST AND A LOT OF POINTS. I NEED A STORY. (If you answer the question and

it's not a real answer I'll report you)
Phases of Matter Activity
Now it is your turn to show what you know about phases of matter and thermal energy transfer! Your task is to create a presentation to explain the transformation of a substance as it changes phases. You may choose to write a story or create a comic strip. For your story or comic, you will create a main character and detail the adventure as your character is exposed to thermal energy, causing it to undergo phase changes from a solid, to a liquid, to a gas. You may create your own comic strip using drawings, presentation software, or this comic strip template.

Your presentation must include the following:

title and introduction of your character, including what substance the character is made of
source of thermal energy your character encountered (conduction, convection, and/or radiation)
detailed description and/or diagram of the particle transformation from solid to liquid phase
detailed description and/or diagram of the particle transformation from liquid to gas phase
You may get creative on this activity. If you are unsure if your idea or software for a presentation will work, contact your instructor for assistance. Be sure to review the grading rubric before you begin.
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
3 0

I got an idea.

This will be a story. (comic can also be done with this. In fact it is better)

The title is the journey of the ice cube. (change it if you want)

Main character - ice cube

There was an ice cube made by the water from the freezer in an ice shop.

The ice cube, with a bunch of other ice cubes, were taken to be packed and sold to a restaurant. The ice cube was excited to where he was going while the other ice cubes are just meh. Now that the ice cubes arrived, a restaurant worker stores the ice cubes in a cooler and later used to put ice in a lemonade. While the lemonade in a glass cup was carried outside the porch of the restaurant by the waiter, the ice cube was fascinated by the environment of the restaurant. The waiter finally serves the thirsty customer and the customer drank almost half of the lemonade but the ice cube did not get in the man's mouth. Instead the other ice cubes went. The ice cube feared the person. Shortly after checking his phone, the customer was about to reach on to the glass until the hands accidentally pushes the glass over and falls. The ice cube and the remaining ice cubes spread away with the wasted lemonade liquid. No one bothered cleaning up the ice cubes, only the glass shards because the floor is a smooth concrete. Outside was really hot from the sun anyways so it would melt the ice cube and sooner evaporate. As it was in liquid form, the "ice cube" was feeling relaxed because it was just chilling on the floor. And when it evaporates, the ice cubes becomes more fascinated since it goes up to the sky while having a sky-view from above.

That is the end.

You can add, edit or even not consider this one. But this is just an example to spark up your ideas. Sorry if I made some English mistakes.

Hope that it helped

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The protein lysozyme unfolds at a transition temperature of 75.5°C, and the standard enthalpy of transition is 509 kJ mol-1. Cal
spin [16.1K]

Answer:

0.4774 KJ/K.mol

Explanation:

We are told that the transition at 25.0°C occurs in three steps. Steps i, ii and iii.

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii

Now,

C_p,m(unfolded protein) = C_p,m(folded protein) + 6.28 kJ/K.mol

Now, for the first process, ΔS_i is given as;

ΔS_i = C_p,m × In(T2/T1)

We are given;

T1 = 25°C = 25 + 273.15K = 298.15 K

T2 = 75.5°C = 75.5 + 273.15 K=348.65 K

Thus;

ΔS_i = C_p,m × In(348.65/298.15)

Now, for the third process, ΔS_iii is given as;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(T1/T2)

Thus;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)

Now, we don't know C_pm. So, we have to find a way to eliminate it. We will do it by rewriting In(298.15/348.65) in such a way that when ΔS_iii is added to ΔS_i, C_p,m will cancel out. Thus;

In(298.15/348.65) can also be written as;

In(348.65/298.15)^(-1) or

- In(348.65/298.15)

Thus;

ΔS_iii = - [(C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)]

Now, let's add ΔS_iii to ΔS_i to get;

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] + [(-C_p,m - 6.28 kJ/K.mol) × In(348.65/298.15)]

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] - [C_p,m × In(348.65/298.15)] - [6.28In(348.65/298.15)]

First 2 terms will cancel out to give;

ΔS_i + ΔS_iii = -6.28In(348.65/298.15)

ΔS_i + ΔS_iii = -0.9826 KJ/K.mol

Now,for process ii;

ΔS_ii = standard enthalpy of transition/Transition Temperature

Thus;

ΔS_ii = (509 KJ/K.mol)/348.65

ΔS_ii = 1.46 KJ/K.mol

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii = -0.9826 + 1.46 = 0.4774 KJ/K.mol

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What is the mass of 3.20x10^23 formula units of iron (III) oxide (Fe2O3)?
yaroslaw [1]

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<h3>Further explanation</h3>

Given

3.20x10²³ formula units

Required

The mass

Solution

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Can be formulated :

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N = number of particles

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mol of Fe₂O₃ :

\tt n=\dfrac{3.2.10^{23}}{6.02.10^{23}}=0.532

mass of Fe₂O₃ (MW=160 g/mol)

\tt mass=mol\times MW=0.532\times 160=85.12~g

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Relative to the mass of the nucleous of a atom. the mass of electron is​
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