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wariber [46]
3 years ago
8

Which of the following is defined as the mass of an atom based on the mass of an atom of carbon-12?

Chemistry
2 answers:
iogann1982 [59]3 years ago
3 0
<span>This would be the atomic mass. In an atom of carbon-12, there are 6 protons and 6 neutrons at rest (electrons have a negligible mass and are usually not part of the overall mass calculation). All atomic masses are based off the measurements of this specific iteration of carbon.</span>
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

atomic mass

Explanation:

done the topic

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SCORPION-xisa [38]
<span>
Evaporation occurred between the reaction of the hydrochloric acid and the arsenic group because there is a formation of gas. A liquid is cooled if condensation exceeds evaporation. This is because the cooling of the liquid decreases the kinetic energy of the molecules. Their movement is being restricted by the colder temperature. The molecules tend to be closer with each other. Also, because of their restricted movement, the liquid may turn into solid due the colder temperature. An example of this is the cooling of liquid water by placing it into the refrigerator into solid water (ice).</span>
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What is one of the BEST practices officers should use when securing a crime scene?
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Answer:

The best practices officers should use when securing a crime scene is option D

D. They should secure a larger area than the actual crime scene

Explanation:

Officers should secure the scene by limiting access to the scene and movement within the scene

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7 0
2 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

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Explanation:

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From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

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Hence, the number of moles produced is 5.25 moles.

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2. The smaller numbers in the image below
ahrayia [7]

Explanation:

The smaller numbers in the image below represents the <u>subscripts</u>.

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