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dedylja [7]
3 years ago
13

A charged particle (q = -8.0 mC), which moves in a region where the only force acting on the particle is an electric force, is r

eleased from rest at point A. At point B the kinetic energy of the particle is equal to 4.8 J. What is the electric potential difference VB - VA?
Physics
1 answer:
ipn [44]3 years ago
3 0

Answer:600 V

Explanation:

 Given

Q=-8 mC

W=4.8 J

And we know

W=QV

V_b-V_a=V_{ba}

4.8=\left ( 8\times 10^{-3} \right )V_{ba}

V_{ba}=0.6\times 10^{-3}

V_{ba}=600 V

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To solve this problem we will apply Newton's second law. The second law says that mass by acceleration is equivalent to the Force exerted on a body. Mathematically this

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Answer:

Explanation:

The best way to do this is to remember the rule about the halfway mark in a parabolic path. At a trajectory's half way point in its travels, it will be at its max height. To get the total time in the air, we take that time at half way and double it. Here's what we know that we are told:

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