Question

A charged particle (q = -8.0 mC), which moves in a region where the only force acting on the particle is an electric force, is released from rest at point A. At point B the kinetic energy of the particle is equal to 4.8 J. What is the electric potential difference VB - VA?

Answer 1

Answer:600 V

Explanation:

 Given

Q=-8 mC

W=4.8 J

And we know

W=QV

$V_b-V_a=V_{ba}$

$4.8=\left ( 8\times 10^{-3} \right )V_{ba}$

$V_{ba}=0.6\times 10^{-3}$

$V_{ba}=600 V$