Well you didn’t post any but I’m hoping that either plastic, lead, wood, glass, or paper, are an option.
Answer : The correct options are,
and 
Explanation :
Single displacement reaction : It is a type of chemical reaction in which the more reactive element displaces the less reactive element.
Option A reaction : 
It is an example of double displacement reaction because in this reaction a positive cation and a negative anion of the two reactants exchange their places to form two new products.
Option B reaction : 
It is an example of single displacement reaction.
Option C reaction : 
It is an example of combination reaction because in this reaction two reactants react to give a single product.
Option D reaction : 
It is an example of decomposition reaction because in this reaction a single reactant decomposes into two or more products.
Option E reaction : 
It is an example of single displacement reaction because in this reaction the most react element, aluminium displaces the less reactive element, hydrogen.
Hence, the options B and E are single displacement reactions.
Answer:
Ranked from lowest to highest:
Sulfur - 999.6 kJ/mol
Hydrogen - 13.5984 kJ/mol
Oxygen - 13.6181 kJ/mol
Fluorine - 17.4228 kJ/mol
Answer:
The determination of the nature of the combination of the two separate materials in the original material that looks pure is based on the characteristic of the change process they undergo to become two separate materials.
Therefore, they can know if they initially had a mixture or a compound by the following steps;
1) If the two separated materials can be easily remixed to form the original material, then they likely have a mixture of the two separate materials
2) If the process that results in the formation of the two separate materials, involves the absorption or evolves heat or other forms of energy, then the original substance was a compound
3) If the two newly formed materials is seen to be a permanent change, then the original material was a compound
Explanation:
PH=-lg[H⁺]
pH=-lg(2.8×10⁻⁹)=8.553
pOH=14-pH
pOH=14-8.553=5.447
[OH⁻]=10^(-pOH)
[OH⁻]=10⁻⁵·⁴⁴⁷=3.6×10⁻⁶