.Earth’s _____________________ is an imaginary line on which it rotate
2 answers:
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The height of the described cylinder is 0.85 cm
Mass= 98g
Density= 8.9g/cm^3
Density= (mass/volume)
Substitute the values
8.94= 98/ volume
Volume=
Volume= 10.97
Volume of a cylinder can be found with (V = π r 2 h.)
h= height of cylinder ?
radius= 2cm
Substitute the values
10.97= π × × h
h= 10.97/12.57
h= 0.85 cm
Therefore, height of the described cylinder is 0.85 cm
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Answer:
8.0 mol/L
Explanation:
To do this problem you need to use C₁V₁=C₂V₂. C=concentration and V=volume. (Note: you dont want to use M₁V₁=M₂V₂ because this is measuring mass not concentration).
So, V₁= 1.0L
C₂=2 Mol/L
V₂= 4 L
C₁ is unknown.
you would plug this equation in like this:
(C₁)(1.0 L)=(2.0 Mol/L)(4.0L).
Do algebra to get C₁ alone.
C₁=
The liters cancel out and you are left with mol/L or M
I hope this helps! good luck :)