The impulse exerted on the ball by the wall is 24i kgm/s.
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Impulse exerted by the ball on the wall</h3>
The impulse exerted by the ball on the wall is the change in the linear momentum of the ball.
J = ΔP
ΔP = Pf - Pi
P = mv
where;
- m is mass of the ball
- v is the velocity
ΔP = 3(4.0i + 3.0j) - 3(-4.0i + 3.0j)
ΔP = (12i + 9j) - (-12i - 9j)
ΔP = 24i kgm/s
Thus, the impulse exerted on the ball by the wall is 24i kgm/s.
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Answer:
maximum amplitude = 0.08 m
Explanation:
Given that
Time period T= 0.58 s
acceleration of gravity g= 9.8 m/s²
We know that time period of simple harmonic motion given as
T = 2π/ω
0.58 = 2π/ω
ω = 10.83rad/s
ω=angular frequency
Lets take amplitude = A
The maximum acceleration given as
a= ω² A
The maximum acceleration should be equal to g ,then block does not separate
a= ω² A
9.8 = 10.83² A
A = 0.08m
maximum amplitude = 0.08 m
The all minerals are pure and free from gangue particles......
Pressure is inversely proportional to volume (at constant temperatures.)
Reducing the volume of a container will increase the gas pressure inside because there will be more collisions of the gas particles with the walls of the container.
The solution and answer are well written in the Pic above.