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3 years ago

The graphs show the motion of an object in both the x and y directions. Classify the motion of this object.

Physics

2 answers:

son4ous [18]3 years ago

8 0

Answer:

Explanation:

Natali5045456 [20]3 years ago

6 0

B It is moving in one dimension

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How does an ocean wave transfer energy across the ocean?

Alborosie

The energy travels in a disturbance, in an ocean that disturbance is a wave, so the wave makes energy and moves it through the water

3 0

4 years ago

The density of gold is 19.3 g cm³. What is the mass of a bar of gold in Kg that measures 6 cm x 4 cmx to 2 cm ?

klemol [59]

Answer: 0.9264 kg

Explanation: [I'll use "cc" for cubic centimeter, instead of cm^3.

The volume is 6cm*4cm*2cm = 48 cm^3 (cc).

Density of Au is 19.3 g/cc

Mass of gold = (48 cc)*(9.3 g/cc) = 926.4 grams Au

1 kg = 1,000 g

(926.4 grams Au)*(1 kg/1,000 g) = 0.9264 kg, 0.93 kg to 2 sig figs

At gold's current price of $57,500/kg, this bar is worth $53,268. Keep it hidden from your lab partner (and instructor).

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3 years ago

A figure skater glides along a circular path of radius 6.70 m. If she coasts around one half of the circle, find the following.

adoni [48]

(a) Her distance from the starting location is 21.05 m.

(b) The length of the path she skated is 21.05 m.

<h3>Distance of the skater from the starting position</h3>

The distance around a complete circular path is calculated as 2πr.

The distance for a half circle is calculated as ¹/₂ x 2πr = πr

Distance from the starting location = π x 6.7 m = 21.05 m

The length of the path she skated is the same as her distance from the starting location = 21.05 m.

Learn more about distance round a circle here: brainly.com/question/3100527

#SPJ1

8 0

2 years ago

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor i

svet-max [94.6K]

Answer:

$0.261\ \text{m}$

Explanation:

$\Delta f$ = Change in frequency = 2.1 Hz

$f$ = Frequency of source of sound = 440 Hz

$v_m$ = Maximum of the microphone

$v$ = Speed of sound = 343 m/s

$T$ = Time period = 2 s

We have the relation

$\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}$

Amplitude is given by

$A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}$

The amplitude of the simple harmonic motion is $0.261\ \text{m}$ .

4 0

3 years ago

parallel-plate capacitor is made of two square plates 25 cm on a side and 1.0 mmapart. The capacitor is connected to a 50.0-V ba

noname [10]

Answer:

6.9 x 10^-7 J

3.5 x 10^-7 J

Explanation:

Identify the unknown:

The energies stored in the capacitor before and after the plates are pulled farther apart

List the Knowns:

Voltage of the battery: V = 50 V

Area of the plates: A = 0.25 x 0.25 = 0.0625 m^2

Original distance between the plates: d = 1 mm = 10^-3 m

New distance between the plates: d = 2 mm = 2 x 10^-3 m

Permittivity of free space: ∈o = 8.85 x 10^-12 C^2/Nm^2-

Set Up the Problem:

Capacitance of a parallel-plate capacitor:

C=∈o*A/d

Energy stored in a capacitor:

U_c=(1/2)*V^2*C

Solve the Problem:

Before the plates are pulled farther apart:

C = 8.85 x 10^-12 x 0.0625/10^-3 = 5•53 x 10^-10 F

U_c = (1/2) x (50)^2 x 5.53 x 10^-10= 6.9 x 10^-7 J

After the plates are pulled farther apart:

C = 8.85 x 10^-12 x 0.0625/2*10^-3 = 2•77 x 10^-10 F

U_c = (1/2) x (50)^2 x 2•77 x 10^-10 = 3.5 x 10^-7 J

The energy decrease because the capacitance decrease, so the stored charge decrease and transferred to the battery

3 0

4 years ago