All categories

3 years ago

The graphs show the motion of an object in both the x and y directions. Classify the motion of this object.

Physics

2 answers:

son4ous [18]3 years ago

8 0

Answer:

Explanation:

Natali5045456 [20]3 years ago

6 0

B It is moving in one dimension

You might be interested in

An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in

Anestetic [448]

Answer:

The value is $a = 4.0 \ m/s^2$

Explanation:

From the question we are told that

The velocity is $a = 120 \ km/h = [tex]\frac{120 * 1000}{3600} = 33.3 \ m/s$ [/tex]

The time taken is $t = 8.28 \ s$

The time taken for contact is $t_c = 0.815 \ s$

The velocity of the of the car after contact is $v_c = 71.0 \ km/h = [tex]\frac{71 *1000}{3600} = 19.7 2 \ m/s$ [/tex]

From the equation of kinematics we have that

$v = u + at$

Here u = 0 \ m/s since the car is initially motionless

=> $33.3 = 0 + a * 8.28$

=> $a = 4.0 \ m/s^2$

4 0

3 years ago

What energy transformation occurs during the combustion of coal in a power plant?

inn [45]

Hello there, the correct answer is:

B.

4 0

3 years ago

Read 2 more answers

A goal is scored soccer when

wel

A goal is scored soccer when the ball crosses the goal line. That is the basic rule in obtaining points in a soccer game. However, there could be circumstances where the referee has the call to determine whether a point is made.

5 0

3 years ago

Read 2 more answers

What is the impulse of a 1700 kg truck traveling at 22.5 m/s?

andrew-mc [135]

Impulse is just the product of mass and speed!

I = 1700 * 22.5 = 38,250 kg m/s

It does not have any special name for its units :(

3 0

3 years ago

A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches

tiny-mole [99]

Answer:

26.8 seconds

Explanation:

To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:

v = final velocity

z = initial velocity

x = distance

t = time

a = acceleration

${v}^{2} = {z}^{2} + 2ax$

$v = z + at$

First let's find the final velocity the plane will have at the end of the runway using the first equation:

${v}^{2} = {0}^{2} + 2(5)(1800)$

$v = 60 \sqrt{5}$

Now we can plug this into the second equation to find t:

$60 \sqrt{5} = 0 + 5t$

$t = 12 \sqrt{5}$

Then using 3 significant figures we round to 26.8 seconds

3 0

2 years ago