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elena-s [515]
3 years ago
11

Consider the incomplete equation below mc020-1.jpg If this equation was completed, which statement would it best support? Nuclea

r fusion produces elements that are heavier than helium. Nuclear fusion produces elements that are lighter than helium. Nuclear fission produces elements that are heavier than helium. Nuclear fission produces elements that are lighter than helium.
Physics
2 answers:
vagabundo [1.1K]3 years ago
8 0
<span>Nuclear fission produces elements that are heavier than helium.

The elements that are used in nuclear fission and their products are much heavier than helium.</span>
Murljashka [212]3 years ago
8 0

Answer:

the anwser is c

Explanation:

You might be interested in
Question 11
kotykmax [81]

Answer:fission

Explanation:

All nuclear power plants rely on fission to generate power

5 0
3 years ago
3 resistors of 3,4 and 12 ohm are there. How would you connect so as to get a resistance more than 5 oh, but less than 7 ohm sho
DochEvi [55]

Answer:

<em>Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below. Please see the file attached below to know the diagram.</em>

Explanation:

There is the following solution that satisfies all requirements indicated on statement:

<em>Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below.</em>

R = \frac{(12\,\Omega)\cdot (4\,\Omega)}{12\,\Omega+4\,\Omega}+3\,\Omega

R = 6\,\Omega

Which observes all design requirements.

4 0
3 years ago
A science student makes the following statement:
Assoli18 [71]

Answer:

A. Forming a Hypothesis

8 0
3 years ago
Read 2 more answers
If the hiker starts climbing at an elevation of 350 ft, what will their change in gravitational potential energy be, in joules,
Kitty [74]

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

7 0
3 years ago
2. A pebble is dropped down a well and hits the water 1.5 s later. Using the equations for motion with constant acceleration, de
kow [346]

Answer:

S = 11.025 m

Explanation:

Given,

The time taken by the pebble to hit the water surface is, t = 1.5 s

Acceleration due to gravity, g = 9.8 m/s²

Using the II equations of motion

                          S = ut + 1/2 gt²

Here u is the initial velocity of the pebble. Since it is free-fall, the initial velocity

                                u = 0

Therefore, the equation becomes

                            S = 1/2 gt²

Substituting the given values in the above equation

                              S = 0.5 x 9.8 x 1.5²

                                 = 11.025 m

Hence, the distance from the edge of the well to the water's surface is, S = 11.025 m

3 0
3 years ago
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