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elena-s [515]
3 years ago
11

Consider the incomplete equation below mc020-1.jpg If this equation was completed, which statement would it best support? Nuclea

r fusion produces elements that are heavier than helium. Nuclear fusion produces elements that are lighter than helium. Nuclear fission produces elements that are heavier than helium. Nuclear fission produces elements that are lighter than helium.
Physics
2 answers:
vagabundo [1.1K]3 years ago
8 0
<span>Nuclear fission produces elements that are heavier than helium.

The elements that are used in nuclear fission and their products are much heavier than helium.</span>
Murljashka [212]3 years ago
8 0

Answer:

the anwser is c

Explanation:

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Anestetic [448]

The answer is wheel and axle

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What is the use of force to move an object over a distance?
steposvetlana [31]

Answer:

In physics, work is defined as the use of force to move an object. For work to be done, the force must be applied in the same direction that the object moves. Work is directly related to both the force applied to an object and the distance the object moves.                                                                                              <em>[I HOPE THIS HELPS* PLS MARK ME BRAINLIEST]</em>

6 0
3 years ago
The Venus flytrap is known for which of these behaviors?
tensa zangetsu [6.8K]
Snapping a leaf shut around an insect, I think.
8 0
2 years ago
Force F=2.0N i - 3.0N k acts on a pebble with position vectorr=0.50m j - 2.0m k relative to the origin. In unit vector notation,
klasskru [66]

Answer with Explanation:

We are given that

Force acts on a pebble=2\hat{i}-3\hat{k} N

Position vector=r=0.5\hat{j}-2\hat{k} m

a.We have to find the resulting torque on the pebble about origin.

Torque=r\times F

Substitute the values then we get

Torque= (0.5j-2k)\times (2i-3k)

Torque=-k-1.5i-4jN-m

By using i\times j=k,j\times k=i,k\times i=j,j\times i=-k,k\times j=-i,i\times k=-j,i\times i=j\times j=k\times k=0

b.r=2i-3k

r-r_1=(0.5j-2k)-(2i-3k)=-2i+0.5j+k

Torque about point (2,0,-3)

\tau=(-2i+0.5j+k)\times (2i-3k)

\tau=-6j-k-1.5i+2j=-1.5i-4j-kN-m

6 0
3 years ago
A refrigerator removes 55.0 kcal of heat from the freezer and releases 73.5 kcal through the condenser on the back.How much work
sammy [17]

Here refrigerator removes 55 kcal heat from freezer

Refrigerator releases 73.5 kcal heat to surrounding

So here we can use energy conservation principle by II Law of thermodynamics

the law says that

Q_1 = Q_2 + W

here we know that

Q_1 = heat released to the surrounding

Q_2 = heat absorbed from freezer

W = work done by the compressor

now using above equation we can write

73.5 = 55 + W

W = 73.5 - 55

W = 18.5 kcal

So here compressor has to do 18.5 k cal work on it

5 0
3 years ago
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