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Inga [223]
3 years ago
6

A flow is isentropically expanded to supersonic speeds in a convergent-divergent nozzle. The reservoir and exit pressures are 1.

0 atm and 0.3143 atm, respectively. What is the value of Ae/A*?
Physics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

Ae/A* = 1.115

Explanation:

Let the reservoir pressure be  p_0

Let the exit  pressure be p_e

Ratio of reservoir pressure and exit pressure

\frac{p_o}{p_e} = \frac{1}{0.3143}

  = 3.182

For the above value of pressure ratio

Obtain the area ratio from the isentropic flow table

Ae/A* = 1.115

The value of pressure ratio is Ae/A* = 1.115

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A charge of 4 nc is placed uniformly on a square sheet of nonconducting material of side 17 cm in the yz plane. (a) what is the
Ratling [72]

The charge density of the sheet is 1.384×10⁻⁷C/m².

Charge density is defined as the charge per unit area.

The sheet is a square of length  l=17 cm.

Calculate the area A of the sheet .

A=l^2=(17 cm)^2= (17*10^-^2m)^2=0.0289 m^2

The charge Q on the sheet is

Q=4nC=4*10^-^9C

The charge density σ is given by,

\sigma=\frac{Q}{A}

Substitute 4×10⁻⁹C for Q and 0.0289 m² for A.

\sigma=\frac{Q}{A}\\ =\frac{4*10^-^9C}{0.0289 m^2} \\ =1.389*10^-^7C/m^2

Thus, the charge density of the sheet is <u>1.384×10⁻⁷C/m².</u>

8 0
3 years ago
During each cycle of operation a refrigerator absorbs 56 cal from the freezer compartment and expels 81 cal tothe room. If one c
Alexandra [31]

Answer:

138.18 minutes

Explanation:

L_v = Latent heat of water at 0°C = 80 cal/g

m = Mass of water = 570 g

Heat removed for freezing

Q=mL_v\\\Rightarrow Q=570\times 80\\\Rightarrow Q=45600\ cal

Let N be the number of cycles and each cycle removes 56 cal from the freezer.

So,

55\times N=45600\\\Rightarrow N=\frac{45600}{55}

Each cycle takes 10 seconds so the total time would be

\frac{45600}{55}\times \frac{10}{60}=138.18\ minutes

The total time taken to freeze 138.18 minutes

6 0
3 years ago
You just found a metallic object in a creek bed. you have found its mass to be 96.5 g, and it displaces 5mL of water. what is th
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Judging by the density (19.3 g/ml) there's a very good chance that it could be gold.
4 0
3 years ago
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Enlarged brain ventricles are presumed to signify __________. A. an excess of dopamine activity B. frontal lobe abnormalities C.
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A buoy is a floating device that can have many purposes, but often as a locator for ships. Collin constructs a hollow metal buoy
Yuri [45]

Answer:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water

B )angular frequency ( w ) = \sqrt{\frac{3g}{h} }

c )  h = 1.34 m ( 4\pi ^{2} / 3g )

Explanation:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water this is because the substances with lesser density floats when placed in a substance with a higher density

B ) when the Buoy is at rest ( t = 0 ) and is then pushed down calculate angular frequency ( w ) of small oscillations in terms of the given variables

volume of cone = hA /3.

h = height of cone, A = Base Area.

therefore the total volume of the Buoy above water level ( at rest )

= (\pi r^{2} * \frac{h}{3} ) * 2 = \frac{\pi r^{2} h  }{6}

The  part of the buoy immersed in water = x

then the net upward force will be

fb ( force of Buoy ) =  fg ( force of gravity )

note force = Mass * Acceleration

force of buoy = \frac{\alpha }{2} *\frac{\pi r^{2}  }{h}* a = ( force of gravity ) \alpha * T\frac{r^{2} }{4} * x * g

therefore a = \frac{3g}{h}  * x

angular frequency ( w ) = \sqrt{\frac{3g}{h} }

C ) height of the each cone

\frac{2\pi }{w}  = 1 therefore w = 2\pi

back to the angular frequency : \frac{3g}{h} = 4\pi ^{2}

therefore h = 1.34 m ( 4\pi ^{2} / 3g )

4 0
3 years ago
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