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maxonik [38]
3 years ago
13

If you rub a balloon on a piece of fabric or carpeting and then hold it against your head, your hair can stand on end.  Use what

you have learned in this lesson to explain why this happens.
Physics
2 answers:
Anon25 [30]3 years ago
3 0
<span>I believe this happens because when you rub the balloon on the carpet or fabric, the connection or contact of that jumbles up the atoms and they receive the energy which makes your hair as the question said 'stand on end' </span>
erik [133]3 years ago
3 0
So when you rub a balloon on a piece of fabric or carpeting and then hold it against your head it has static electrocute that causes your hair to stand on end
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A new pest is found that only feeds on corn plant leaves. Which promoter would you choose if the modified gene produces toxins t
8090 [49]

It is actually B. Promoter 2.

Your welcome

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5 0
3 years ago
A series RLC circuit has a resonant frequency = 6.00 kHz. When it is driven at a frequency = 8.00 kHz, it has an
ANEK [815]

The resistance (R) of the circuit is 707.1 ohms and the inductance (L) is 0.032 H.

<h3>Resistance of the circuit</h3>

For the phase constant of 45⁰, impedance is equal to the resistance of the circuit.

Z= R\sqrt{2} \\\\R  = \frac{Z}{\sqrt{2} } \\\\R = \frac{1000}{\sqrt{2} } = 707.1 \ ohms

<h3>Resonant frequency</h3>

f = \frac{1}{2\pi \sqrt{LC} } \\\\6000 = \frac{1}{2\pi \sqrt{LC} } \\\\2\pi(6000) = \frac{1}{\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi (6000)} \\\\LC = (\frac{1}{2\pi (6000)})^2\\\\LC = 7.034 \times 10^{-10} \\\\ C = \frac{7.034 \times 10^{-10} }{L} ---(1)

<h3>At driven frequency</h3>

X_l- X_c = R\\\\\omega L - \frac{1}{\omega C}  = 707.1\\\\2\pi f L -  \frac{1}{2\pi fC} = 707.1\\\\2\pi (8000) L - \frac{1}{2\pi (8000) C } = 707.1\ \ --(2)\\\\

<em>solve 1 and 2 together</em>

2\pi(8000) L - \frac{L}{2\pi (8000)(7.034 \times 10^{-10})} = 707.1\\\\50272L - 28279.48L = 707.1\\\\L = 0.032 \ H

Learn more about impedance of RLC circuit here: brainly.com/question/372577

7 0
3 years ago
Muons are elementary particles that are formed high in the atmosphere by the interactions of cosmic rays with atomic nuclei. Muo
uysha [10]

Answer:

<em>Muons reach the earth in great amount due to the relativistic time dilation from an earthly frame of reference.</em>

Explanation:

Muons travel at exceedingly high speed; close to the speed of light. At this speed, relativistic effect starts to take effect. The effect of this is that, when viewed from an earthly reference frame, their short half life of about two-millionth of a second is dilated. The dilated time, due to relativistic effects on time for travelling at speed close to the speed of light, gives the muons an extended relative travel time before their complete decay. So <em>in reality, the muon do not have enough half-life to survive the distance from their point of production high up in the atmosphere to sea level, but relativistic effect due to their near-light speed, dilates their half-life; enough for them to be found in sufficient amount at sea level.  </em>

5 0
3 years ago
Why does friction increase as speed increases??
kozerog [31]
Friction is directly related to air particles.

When we say that friction is high, it means that you're colliding with lots of air particles, and hence you can't speed up as easily.
Thus, the more air particles you encounter, the higher the friction.

The faster you go, the more particles you will encounter in a given time; hence at higher speeds, the friction is higher.
7 0
3 years ago
A baby carriage is sitting at the top of a hill that is 21 m high The carriage with the baby weighs 12 N
WITCHER [35]

Answer:E

=

252

J

Explanation:

The total mechanical energy of an object or system is given by:

E

m

e

c

h

=

K

+

U

Where

K

is the kinetic energy of the object and

U

is the potential energy of the object. The carriage, sitting motionless at the top of the hill, has only potential energy in the form of gravitational potential energy.

Gravitational potential energy is given by:

U

g

=

m

g

h

Where

m

is the mass of the object,

g

is the gravitational acceleration constant, and

h

is the height of the object above some specific reference point, in this case the ground

21

m

below.

The weight of a stationary object at the surface of the earth is equal to the force of gravity acting on the object.

W

=

→

F

g

=

m

g

We are given that the carriage weighs

12

N

, therefore

m

g

=

12

N

.

U

g

=

12

N

⋅

21

m

⇒

U

g

=

252

N

m

=

252

J

Answer link

Explanation:

5 0
3 years ago
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