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Zina [86]
3 years ago
13

I just need help with these seven!

Physics
1 answer:
Anna [14]3 years ago
5 0
21. light changes its direction when travelling through a new medium because denser mediums have a higher angle of refraction.
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How do lines of latitude affect how direct or indirect the Sun’s rays are on the Earth?
Sonja [21]

Answer:

Explanation:  We have seasons because Earth's axis – the imaginary line that goes through the Earth and around which the Earth spins — is tilted. It's tilted about 23.5 degrees relative to our plane of orbit (the ecliptic) around the Sun. As we orbit our Sun, our axis always points to the same fixed location in space. Our northern axis points almost directly toward Polaris, the North Star.

6 0
3 years ago
A thin rod rotates at a constant angular speed. Consider the tangential speed of each point on the rod for the case when the axi
ASHA 777 [7]

Answer:

    v = R w    

With this expression we see that for each point at different radius the tangential velocity is different

Explanation:

They indicate that the angular velocity is constant, that is

            w = dθ / dt

Where θ is the radius swept angle and t the time taken.

The tangential velocity is linear or

           v = dx / dt

Where x is the distance traveled in time (t)

 

In the definition of radians

          θ = s / R

Where s is the arc traveled and R the radius vector from the pivot point, if the angle is small the arc (s) and the length (x) are almost equal

         θ = x / R

We substitute in the speed equation

         v = d (θ R) / dt

The radius is a constant for each point

         v = R dθ / dt

         v = R w

With this expression we see that for each point at different radius the tangential velocity is different

6 0
3 years ago
In a cyclotron, the orbital radius of protons with energy 300 keV is 16.0 cm . You are redesigning the cyclotron to be used inst
Archy [21]

Answer:

16 cm

Explanation:

For protons:

Energy, E = 300 keV

radius of orbit, r1 = 16 cm

the relation for the energy and velocity is given by

E = \frac{1}{2}mv^{2}

So, v = \sqrt{\frac{2E}{m}}   .... (1)

Now,

r = \frac{mv}{Bq}

Substitute the value of v from equation (1), we get

r = \frac{\sqrt{2mE}}{Bq}

Let the radius of the alpha particle is r2.

For proton

So, r_{1} = \frac{\sqrt{2m_{1}E}}{Bq_{1}}    ... (2)

Where, m1 is the mass of proton, q1 is the charge of proton

For alpha particle

So, r_{2} = \frac{\sqrt{2m_{2}E}}{Bq_{2}}    ... (3)

Where, m2 is the mass of alpha particle, q2 is the charge of alpha particle

Divide equation (2) by equation (3), we get

\frac{r_{1}}{r_{2}}=\frac{q_{2}}{q_{1}}\times \sqrt{\frac{m_{1}}{m_{2}}}

q1 = q

q2 = 2q

m1 = m

m2 = 4m

By substituting the values

\frac{r_{1}}{r_{2}}=\frac{2q}}{q}}\times \sqrt{\frac{m}}{4m}}=1

So, r2 = r1 = 16 cm

Thus, the radius of the alpha particle is 16 cm.

8 0
3 years ago
Read 2 more answers
PLEASE HELP:( urgent!!
never [62]
Fnet =ma
1560)(1.3102)
the answer is b
7 0
2 years ago
What is the total momentum of a 30 kg object traveling left at 3 m/s and a 50 kg object traveling at 2 m/s to the right?
madam [21]

Answer:

there are 25 kg objective travelling at 2m/s to the right.

4 0
2 years ago
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