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3 years ago

Which astronomer spent 20 years plotting the positions of the planets

Physics

2 answers:

dalvyx [7]3 years ago

6 0

Answer

Tycho Brahe

Explanation

Tycho Brahe who was born on 1546. He was an astronomer.Tycho Brahe spent 20 years in plotting the positions of the planets and he was among those astronomers who helped in giving the heliocentric model of the universe..

klio [65]3 years ago

5 0

That was Tycho Brahe, and I thought it was actually more years than that.

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Charra [1.4K]

Answer: A

Explanation:

8 0

3 years ago

A stone is catapulted at time t = 0, with an initial velocity of magnitude 19.9 m/s and at an angle of 39.9° above the horizonta

larisa [96]

Answer:

Part a)

$x = 15.76 m$

Part b)

$y = 7.94 m$

Part c)

$x = 26.16 m$

Part d)

$y = 7.49 m$

Part e)

$x = 83.23 m$

Part f)

$y = -75.6 m$

Explanation:

As we know that catapult is projected with speed 19.9 m/s

so here we have

$v_x = 19.9 cos39.9$

$v_x = 15.3 m/s$

similarly we have

$v_y = 19.9 sin39.9$

$v_y = 12.76 m/s$

Part a)

Horizontal displacement in 1.03 s

$x = v_x t$

$x = (15.3)(1.03)$

$x = 15.76 m$

Part b)

Vertical direction we have

$y = v_y t - \frac{1]{2}gt^2$

$y = (12.76)(1.03) - 4.9(1.03)^2$

$y = 7.94 m$

Part c)

Horizontal displacement in 1.71 s

$x = v_x t$

$x = (15.3)(1.71)$

$x = 26.16 m$

Part d)

Vertical direction we have

$y = v_y t - \frac{1]{2}gt^2$

$y = (12.76)(1.71) - 4.9(1.71)^2$

$y = 7.49 m$

Part e)

Horizontal displacement in 5.44 s

$x = v_x t$

$x = (15.3)(5.44)$

$x = 83.23 m$

Part f)

Vertical direction we have

$y = v_y t - \frac{1]{2}gt^2$

$y = (12.76)(5.44) - 4.9(5.44)^2$

$y = -75.6 m$

6 0

3 years ago

Find the final velocity if the initial velocity of 8 m/s with an acceleration of 7 m/s2 over a 3 second interval?

LenKa [72]

I don't know about it your answer will give another people

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3 years ago

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jenyasd209 [6]

Is this a true or false question?

5 0

4 years ago

Given one mole of diamond vs one mole of graphite,

grandymaker [24]

Answer:

The pressure is $P= - 6.39*10^8Pa$

The temperature is $T =1218.63 K$

Explanation:

Generally Gibbs free energy is mathematically represented as

$G = E + PV -TS$

Where E is the enthalpy

PV is the pressure volume energy (i.e PV energy)

S is the entropy

T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

So at temperature of T = 300 K

$E + PV - TS = 0$

making P the subject

$P = \frac{TS-E}{V}$

Now substituting 300 K for T , 2900 J for E ,

$3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3$ for V and $2.38 J/K$ for S

$P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}$

$P= - 6.39*10^8Pa$

The negative sign signifies the direction of the pressure

Given that $P = 1*0^5Pa$

making T the subject

$T = \frac{PV+E}{S}$

Substituting into the equation

$T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}$

$T =1218.63 K$

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3 years ago

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