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Vlad [161]
2 years ago
9

16+6-6x-4=-7x+3+7how to solve for x​

Mathematics
2 answers:
Alla [95]2 years ago
5 0

Answer:

x = -8

Step-by-step explanation:

16+6-6x-4=-7x+3+7

Combine like terms

18 -6x = -7x+10

Add 7x to each side

18-6x+7x = -7x+7x+10

18+x = 10

Subtract 18 from each side

18+x-18 = 10-18

x = -8

Ahat [919]2 years ago
5 0

Answer:

x = -8

Step-by-step explanation:

16+6-6x-4 = -7x+3+7

18 - 6x = -7x + 10

-6x + 7x = 10 - 18

x = -8

Check:

18 - 6*-8 = -7*-8 + 10

18 + 48 = 56 + 10 = 66

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Answer:

Leg side along the wall = x ft = 8 ft

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Step-by-step explanation:

In the question, the shape of the pool is right triangle.

Let the leg side along the wall to be the x ft

Let the other leg side  to be 7+x ft

Let the longest side/hypotenuse to be x+9 ft

Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse

This means;

x^2 +(x+7)^2=(x+9)^2\\\\

Expand the terms in brackets

x^2+(x+7)^2=(x+9)^2\\\\\\x^2+x^2+14x+49=x^2+18x+81

collect like terms

x^2+x^2-x^2=18x-14x+81-49\\\\\\x^2=4x+32\\\\\\x^2-4x-32=0

solve for x in the quadratic equation by factorization

x^2-4x-32=0\\\\\\x^2-8x+4x-32=0\\\\\\x(x-8)+4(x-8)=0\\\\\\(x+4)(x-8)=0\\\\\\x+4=0,x=-4\\\\x-8=0,x=8

Taking the positive value of x;

x=8ft

Finding the lengths

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

6 0
3 years ago
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