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Andrew [12]
3 years ago
13

A system uses 2380 I of energy to do work as 12,900 j of heat are added to the system. The change in internal energy of the syst

em is
Physics
1 answer:
sergey [27]3 years ago
4 0
The internal energy of the system is characterized by the equation U = Q + W where U is the internal energy, Q is the heat and W is work. You are given 2,380 J of energy to do work as 12,900 J of heat so add up. The internal energy is 15,280J.



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A massive object can distort the light of more distant objects behind it through the phenomenon that we call __________
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Answer:

Gravitational lensing

Explanation:

In general relativity, the path of light will get deflected due to presence of matter. This is because matter can curve spacetime.

8 0
3 years ago
Two football players with mass 75 kg and 100 kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively. if t
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<u><em>heyaaaaa</em></u>

<u><em>Momentum before Pb = momentum after Pa</em></u>

Pb = 75*6 - 100*8 = -350kgm/s = Pa = (75+100)V where V is the velocity of the combined mass of the two players after the collision.

<u><em>Velocity has magnitude (speed) and direction. V = -350/175 = -2m/s </em></u>

So the two players are moving at 2m/s in the direction the 100kg player was moving before the collision.

<em><u>I arbitrarily chose the direction of the smaller player as positive so the opposite direction (of the larger player) had to be negative. </u></em>

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3 years ago
you want to get more physically fit but often make excuses for why you don't have time to be active what strategy can help with
Anna35 [415]
<span>Find an activity you enjoy and make it a priority in your schedule.</span>
6 0
3 years ago
A pogo stick has a spring with a force constant of 2.50 × 104 N/m , which can be compressed 11.2 cm. what maximum height, in met
AleksandrR [38]

Answer:

h = 36.4 cm

Explanation:

given,

spring constant = 2.5 x 10⁴ N/m

compressed distance = 11.2 cm = 0.112 m

mass of the child = 44 kg

maximum height = ?

by energy of conservation

K.E_i +P.E_i= K.E_f + P.E_f

\dfrac{1}{2}kx^2 = mgh

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

156.8 = 44 \times 9.8 \times h

h = \dfrac{156.8}{44 \times 9.8}

h = 0.364 m

h = 36.4 cm

7 0
3 years ago
An ice skater is spinning at 6.00 rev/s with his moment of inertia being 0.400 kg/m2. Calculate his new moment of inertia if he
labwork [276]

Answer:

New moment of inertia will be I=1.92kgm^2

Explanation:

It is given initially angular velocity \omega =6rev/sec=6\times 2\pi =37.68rad/sec

Moment of inertia I=0.4kgm^2

Angular momentum is equal to L=I\omega =37.68\times 0.4=15.072kgm^2/sec

Now angular velocity is decreases to \omega =1.25rev/sec=1.25\times 2\times 3.14=7.85rad/sec

As we know that angular momentum is conserved

So 15.072=I\times 7.85

I=1.92kgm^2

So new moment of inertia will be I=1.92kgm^2

4 0
4 years ago
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