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Andrew [12]
3 years ago
13

A system uses 2380 I of energy to do work as 12,900 j of heat are added to the system. The change in internal energy of the syst

em is
Physics
1 answer:
sergey [27]3 years ago
4 0
The internal energy of the system is characterized by the equation U = Q + W where U is the internal energy, Q is the heat and W is work. You are given 2,380 J of energy to do work as 12,900 J of heat so add up. The internal energy is 15,280J.



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How long does it take a car traveling at 45km/h to travel 100 m
AysviL [449]

Explanation:

45 \frac{km}{hr}  \times  \frac{1000m}{1km}  = 45000 \frac{m}{hr}  \\  \frac{100m}{45000 \frac{m}{hr} }  =  \frac{1}{450} hr \\  \frac{1}{450} hr \times  \frac{60mins}{1hr}  =  \frac{2}{15} mins = 0.133mins

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Question: Why do both the moon and the earth pull on the spaceship the entire time? Why must you be closer to the moon before th
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-- There's no limit to the distance of gravitational forces. 
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Even before it's ever launched !

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While attempting a landing on the moon, astronauts had to change their landing site and land at a spot that was 4 kilometers awa
lesya [120]
The closest answer would be C.
The choices given do not give the exact value. 

To answer this, you just need to remember the main formula:

d = Vit + \frac{1}{2}gt^{2}

Where:
d = distance/displacement
g = acceleration due to gravity
t = time in flight
Vi = initial velocity.

With this formula, you derive all the formulas you need to look for certain components. You need to keep in mind of the following:

---if you are looking for a vertical component(y), you need to use values of vertical motion.

dy = Viyt + \frac{1}{2}gt^{2}

*Viy is always 0m/s at the beginning of a free-fall.

dy = (0m/s)t + \frac{1}{2}gt^{2}

                                             dy = \frac{1}{2}gt^{2}

---If you are looking for a horizontal component(x), you need to use values of horizontal motion. 

dx = Vixt + \frac{1}{2}gt^{2}

*g is always 0m/s² when taking horizontal motion into account. 

dx = Vixt + \frac{1}{2}(0m/s^{2})t^{2}

                                                       dx = Vixt
--- time is the only value that is both vertical and horizontal. 

Okay, let's get back to solving your problem. Let's see what your given is first:
dy = 137m (as long as it refers to height, it is vertical distance)
dx = 4km (the word, far or away usually indicates horizontal distance)
g = 1.63m/s²

The question is how fast was it going horizontally and we can derive it from our equation:

 dx = Vixt

We use this because x means horizontal. But notice that we do not have time yet. So how are we going to solve this 2 variables missing? The key is that time is a horizontal and vertical component. Whatever time it took moving horizontally, it is the same vertically as well. So we use the vertical formula to derive time:

dy = \frac{1}{2}gt^{2}
\frac{2dy}{g}=t^{2}
\sqrt{\frac{2dy}{g}} = \sqrt{t^{2}}
                                           \sqrt{\frac{2dy}{g}} = t

Now plug in what you know and solve for what you don't know:

\sqrt{\frac{2(137m)}{1.63m/s^{2}}} = t
\sqrt{\frac{274m}{1.63m/s^{2}}} = t
\sqrt{168.098s^{2}}=t
12.965s = t

The total time in flight is 12.965s.
Let's round it off to 13s. 

Now that we know that, we can use this in the horizontal formula:
dx = Vixt
4km = Vix(13s)

Hold up! Look at the unit of the horizontal distance. It is in km but all our units are expressed in m so we need to convert that first.

1km = 1,000m
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Our new horizontal distance is 4,000m.

Okay, let's wrap this up by solving for what is asked for, using all the derived values. 
dx = Vixt
4,000m = Vix(13s)
\frac{4,000m}{13s} = Vix
308m/s= Vix

The horizontal velocity is 308m/s. 

Such a long explanation I know, but hopefully, you learned from it. 
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Answer:

A disk formed of a long trail of stars coiled into a spiral.

Explanation:

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