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dusya [7]
3 years ago
7

Bosons & Fermions A new type of quantum object has been discovered. When a large collection of these are cooled to almost ab

solute zero, they are observed to all condense into the same state - the ground state. Select all that are True.
Is this object a Fermion obeying Fermi-Dirac statistics?
Is this object a Boson obeying Bose-Einstein statistics?
Could this object have intrinsic spin 2 hbar?
Would the Schrodinger equation for two of these particles be symmetric with exchange of the two particles?
Could this object have intrinsic spin s = 3/2 hbar?
Would the Schrodinger equation for two of these particles be anti-symmetric with exchange of the two particles?
Physics
1 answer:
Lena [83]3 years ago
5 0

Answer:

Only 2,3,4 are true

Explanation:

Bosons Particles are particles that condense to the same state. Bosons particle have integral spin like 0 , $\hbar$, 2$\hbar, 3$\hbar$, etc. Bosons particles always have asymmetric wave function and there is exchange of particles.

1) It does not obey Fermi_ Dirac statistics

2) It obeys Bose-Einstein statistics

3) The object can have intrinsic spin 2$\hbar

4) Yes the Bosons particle is always symmetric with exchange of particles

5) No Bosons particle are symmetric and not asymmetric

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AlekseyPX
The density of the material would be 
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density is calculated as: (the mass of the given material or object) / volume of the material 
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3 years ago
An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elec
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Answer:

Speed = 575 m/s

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Explanation:

Given :

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Mass of the alpha particle, $m_{\alpha} = 6.68 \times 10^{-27} \ kg$

Charge of the alpha particle is, $q_{\alpha} = 3.20 \times 10^{-19} \ C$

So the potential difference for the alpha particle when it is accelerated through the potential difference is

$U=\Delta Vq_{\alpha}$

And the kinetic energy gained by the alpha particle is

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From the law of conservation of energy, we get

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$\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$

$v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$

$v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$

$v_{\alpha} \approx 575 \ m/s$

The mechanical energy is conserved in the presence of the following conservative forces :

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True

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Hope this helps!

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~ Ria

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