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dusya [7]
3 years ago
7

Bosons & Fermions A new type of quantum object has been discovered. When a large collection of these are cooled to almost ab

solute zero, they are observed to all condense into the same state - the ground state. Select all that are True.
Is this object a Fermion obeying Fermi-Dirac statistics?
Is this object a Boson obeying Bose-Einstein statistics?
Could this object have intrinsic spin 2 hbar?
Would the Schrodinger equation for two of these particles be symmetric with exchange of the two particles?
Could this object have intrinsic spin s = 3/2 hbar?
Would the Schrodinger equation for two of these particles be anti-symmetric with exchange of the two particles?
Physics
1 answer:
Lena [83]3 years ago
5 0

Answer:

Only 2,3,4 are true

Explanation:

Bosons Particles are particles that condense to the same state. Bosons particle have integral spin like 0 , $\hbar$, 2$\hbar, 3$\hbar$, etc. Bosons particles always have asymmetric wave function and there is exchange of particles.

1) It does not obey Fermi_ Dirac statistics

2) It obeys Bose-Einstein statistics

3) The object can have intrinsic spin 2$\hbar

4) Yes the Bosons particle is always symmetric with exchange of particles

5) No Bosons particle are symmetric and not asymmetric

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Answer:

a

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Explanation:

From the question we are told that  

   The  wavelength of the light is \lambda  = 550 \ nm  =  550 *10^{-9} \ m

    The  distance of the slit separation is  d = 0.500 \ mm = 5.0 *10^{-4} \ m

 

Generally the condition for two slit interference  is  

     dsin \theta =  m \lambda

Where m is the order which is given from the question as  m = 2

=>    \theta  =  sin ^{-1} [\frac{m \lambda}{d} ]

 substituting values  

      \theta  =  0.0022 rad

Now on the second question  

   The distance of separation of the slit is  

       d =  0.300 \ mm  =  3.0 *10^{-4} \ m

The  intensity at the  the angular position in part "a" is mathematically evaluated as

      I  =  I_o  [\frac{sin \beta}{\beta} ]^2

Where  \beta is mathematically evaluated as

       \beta  =  \frac{\pi *  d  *  sin(\theta )}{\lambda }

  substituting values

     \beta  =  \frac{3.142  *  3*10^{-4}  *  sin(0.0022 )}{550 *10^{-9} }

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So the intensity is  

    I  =  I_o  [\frac{sin (0.06581)}{0.06581} ]^2

   I  =  0.000304 I_o

3 0
3 years ago
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Answer:

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