Answer:
the middle
Explanation:
the left one bulb gets power from the outher bulb
the one on right has more bulbs
Answer:
<h3>The answer is 1400 J</h3>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 20 × 10 × 7
We have the final answer as
<h3>1400 J</h3>
Hope this helps you
Radio Waves :)) i’m pretty confident in that
The magnitude of <em>electrical</em> force on charge
due to the others is 0.102 newtons.
<h3>
How to calculate the electrical force experimented on a particle</h3>
The vector <em>position</em> of each particle respect to origin are described below:
![\vec r_{1} = (-0.500, 0)\,[m]](https://tex.z-dn.net/?f=%5Cvec%20r_%7B1%7D%20%3D%20%28-0.500%2C%200%29%5C%2C%5Bm%5D)
Then, distances of the former two particles particles respect to the latter one are found now:
![\vec r_{13} = (+0.500, +0.500)\,[m]](https://tex.z-dn.net/?f=%5Cvec%20r_%7B13%7D%20%3D%20%28%2B0.500%2C%20%2B0.500%29%5C%2C%5Bm%5D)


![\vec r_{23} = (-0.500, +0.500)\,[m]](https://tex.z-dn.net/?f=%5Cvec%20r_%7B23%7D%20%3D%20%28-0.500%2C%20%2B0.500%29%5C%2C%5Bm%5D)


The resultant force is found by Coulomb's law and principle of superposition:
(1)
Please notice that particles with charges of <em>same</em> sign attract each other and particles with charges of <em>opposite</em> sign repeal each other.
(2)
Where:
- Electrostatic constant, in newton-square meters per square Coulomb.
,
,
- Electric charges, in Coulombs.
,
- Distances between particles, in meters.
,
- Unit vectors, no unit.
If we know that
,
,
,
,
,
,
and
, then the vector force on charge
is:

![\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%200.072%5Ccdot%20%5Cleft%28-%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%2C%20-%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%20%5Cright%29%20%2B%200.072%5Ccdot%20%5Cleft%28%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%2C%20-%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%20%5Cright%29%5C%2C%5BN%5D)
![\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%200.072%5Ccdot%20%5Cleft%280%2C%20-%5Csqrt%7B2%7D%5Cright%29%5C%2C%5BN%5D)
And the magnitude of the <em>electrical</em> force on charge
(
), in newtons, due to the others is found by Pythagorean theorem:

The magnitude of <em>electrical</em> force on charge
due to the others is 0.102 newtons. 
To learn more on Coulomb's law, we kindly invite to check this verified question: brainly.com/question/506926
Answers:
a) 0.144 Hz
b) 0.904 rad/s
c) 11.818 m
d)
Explanation:
The rest of the question is written below:
a) Calculate the frequency of oscillation (in Hertz) of the chandelier
b) Calculate the angular frequency
of the chandelier in radians/ second
c) Determine the length
in meters of the chandelier
d) That evening, while hanging out in JJ. Thompson's House O' Blues, you notice that (coincidentally) there is a chandelier identical in every way to the one at the Michelson exhibit except this one swings back and forth 0.01 seconds slower, so the period is
. Determine the acceleration due to gravity in
at the club.
a) The frequency
has an inverse relation with the period
:
(1)
Where 
(2)
b) The angular frequency
is given by:
(3)
(4)
(5)
c) Another expression for the period is:
(6)
Where:
is the length of the pendulum
is the mean acceleration due gravity
Isolating
:
(7)
(8)
(9)
d) In this case the period of the pendulum is
. So, we will use equation (7) with this period and find
:
(10)
(11)
(12) This is the acceleration due gravity at the place, which is near the mean value of 