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nignag [31]
2 years ago
5

consider the graph of the following qudratic equation. y= -x^2 -10x + 24.What is the y-value of the vertex?

Mathematics
1 answer:
3241004551 [841]2 years ago
8 0

Given that the quadratic equation is y=-x^{2}-10 x+24

We need to determine the y - value of the vertex.

<u>The x - value of the vertex:</u>

The x - value of the vertex can be determined using the formula,

x=-\frac{b}{2 a}

where a=-1, b=-10, c=24

Substituting these values, we get;

x=-\frac{(-10)}{2(-1)}

Simplifying the terms, we get;

x=-\frac{-10}{-2}

x=-5

Thus, the x - value of the vertex is -5.

<u>The y - value of the vertex:</u>

The y - value of the vertex can be determined by substituting the x - value of the vertex ( x = -5) in the equation y=-x^{2}-10 x+24

Thus, we get;

y=-(-5)^{2}-10(-5)+24

Simplifying the values, we have;

y=-25+50+24

y=49

Thus, the y - value of the vertex is 49.

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