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Anna71 [15]
2 years ago
7

Use the equation to answer the question.

Chemistry
2 answers:
aniked [119]2 years ago
6 0

The equation is an example of beta-minus decay.

In a beta-minus decay, an electron is converted to a proton. When this happens, the atomic number of the daughter nucleus increases by one unit above the atomic number of the parent nucleus.

Looking at the equation, we can see that the atomic number of the daughter nucleus increased by one unit above that of the parent nucleus while the mass number of both the parent nucleus and daughter nucleus remained the same. Therefore, a beta-minus decay has taken place.

Learn more: brainly.com/question/792111

iogann1982 [59]2 years ago
4 0

Answer:

1. D

2. B

3. A

4. B

5. A

Explanation: just finished quick check

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A higher amplitude means...?
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High amplitude is equivalent to loud sounds.

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2 years ago
How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g
Serhud [2]

<u>Answer:</u> The energy released for the decay of 3 grams of 230-Thorium is 2.728\times 10^{-15}J

<u>Explanation:</u>

First we have to calculate the mass defect (\Delta m).

The equation for the alpha decay of thorium nucleus follows:

_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

\Delta m=(m_{Ra}+m_{He})-(m_{Th})

\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg

(Conversion factor: 1amu=1.66\times 10^{-27}kg )

To calculate the energy released, we use Einstein equation, which is:

E=\Delta mc^2

E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2

E=2.0916\times 10^{-13}J

The energy released for 230 grams of decay of thorium is 2.0916\times 10^{-13}J

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = 2.0916\times 10^{-13}J

Then, 3 grams of Th will release energy of = \frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J

Hence, the energy released for the decay of 3 grams of 230-Thorium is 2.728\times 10^{-15}J

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Why are stars special sources of light?(2 points)
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They give off their own light energy

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