Which of the following is the most usable form of nitrogen to plants?

A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the insta

MissTica

For a flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω, the rate of energy being delivered is mathematically given as

P= 53 W

<h3>What rate is energy being delivered by the battery?</h3>

Generally, the equation for the Battery power is mathematically given as

P = I (dt)V

Therefore

P= 2.50 A * 21.2V

P= 53 W

In conclusion, rate of energy being delivered

P= 53 W

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7 0

2 years ago

24. A total of 165 J of work is done on a gaseous refrigerant as it undergoes compression. If the internal energy of the gas inc

Yuliya22 [10]

The total amount of energy transferred as heat is equal to 288 Joules.

<u>Given the following data:</u>

Internal energy = 123 Joules

Work done = 165 Joules

To calculate the total amount of energy transferred as heat, we would apply the first law of thermodynamics.

<h3>The first law of thermodynamics.</h3>

Mathematically, the first law of thermodynamics is given by the formula:

$\Delta E = Q - W$

<u>Where;</u>

$\Delta E$ is the change in internal energy.

Q is the quantity of heat transferred.

W is the work done.

Substituting the given parameters into the formula, we have;

$123 = Q - 165\\\\Q=123+165$

Q = 288 Joules.

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4 0

2 years ago

Two horizontal rods are each held up by vertical strings tied to their ends. Rod 1 has length L and mass M; rod 2 has length 2L

antiseptic1488 [7]

Answer:

Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.

Explanation:

For the rod 1 the angular acceleration is

$\tau_1 = I_1\alpha _1 \\\\\alpha_1 = \dfrac{\tau_1}{I_1}$

Similarly, for rod 2

$\alpha_2 = \dfrac{\tau_2}{I_2}.$

Now, the moment of inertia for rod 1 is

$I_1 = \dfrac{1}{3}ML^2$ ,

and the torque acting on it is (about the center of mass)

$\tau_1 = Mg\dfrac{L}{2};$

therefore, the angular acceleration of rod 1 is

$\alpha_1 = \dfrac{Mg\dfrac{L}{2}}{\dfrac{1}{3}ML^2},$

$\boxed{\alpha_1 = \dfrac{3g}{2L} }$

Now, for rod 2 the moment of inertia is

$I_2 = \dfrac{1}{3}(2M)(2L)^2$

$I_2 = \dfrac{8}{3} ML^2,$

and the torque acting is (about the center of mass)

$\tau _2 = (2M)g \dfrac{(2L)}{2}$

$\tau _2 = 2MgL;$

therefore, the angular acceleration $\alpha_2$ is

$\alpha_2 = \dfrac{2MgL;}{\dfrac{8}{3} ML^2,}.$

$\boxed{\alpha_2 = \dfrac{3g}{4L}}$

We see here that

$\dfrac{3g}{2L} > \dfrac{3g}{4L}$

therefore

$\boxed{\alpha_1 > \alpha_2.}$

In other words , the initial angular acceleration for rod 1 is greater than for rod 2.

7 0

2 years ago

vector a having mignitude 3.2 makes 50degre with x-axis and vector b with magnitude 5.2 makes 110degre with x-axis what is the m

Svetllana [295]

Yep ask google good idea

8 0

3 years ago

Whats is physical energy

vampirchik [111]

Is related to interfere on raw physical matter (Masses and Bodies)

7 0

3 years ago

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